tìm số nguyên x, biết:
giúp tớ nhé
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a) \(2a=3b=4c\)
\(\Rightarrow\dfrac{a}{6}=\dfrac{b}{4}=\dfrac{c}{3}\)
Áp dụng t/c dtsbn:
\(\dfrac{a}{6}=\dfrac{b}{4}=\dfrac{c}{3}=\dfrac{a-b+c}{6-4+3}=\dfrac{35}{5}=7\)
\(\Rightarrow\left\{{}\begin{matrix}a=7.6=42\\b=7.4=28\\c=7.3=21\end{matrix}\right.\)
b) \(21x=19y\Rightarrow\dfrac{x}{19}=\dfrac{y}{21}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{19}=\dfrac{y}{21}=\dfrac{2x}{38}=\dfrac{y-2x}{21-38}=\dfrac{-34}{-17}=2\)
\(\Rightarrow\left\{{}\begin{matrix}x=2.19=38\\y=2.21=42\end{matrix}\right.\)
\(\left(74.25+\dfrac{3}{4}\right)\times x-131.5=18.5\)
\(\left(74.25+0.75\right)\times x=18.5+131.5\)
\(75\times x=150\)
\(x=150:75\)
\(x=2\)
`(74,25 + 3/4) xx x-131,5 =18,5`
`75xx x=18,5 + 131,5`
`75 xx x =150`
`x=150:75`
`x = 2`
4-(27-3)=x-(13-4)
=>-20=x-(13-4)
=>-20=x-9
=> x=-20+9
=> x=-11
Vậy x = -11
4 - 27 + 3 = x - 13 + 4
-x = -13 + 4 - 4 + 27 - 3
-x = 11
=> x = -11
ta có : 2(x-3)=3(y-2)
2x-6=3y-6
2x=3y hay 2x-2y=y
2(x-y)=y
y=2.4=8;x=2.8:3=6
a: 461+(x-45)=387
=>\(x-45=387-461=-74\)
=>\(x=-74+45=-29\)
b: \(15\cdot23-85\cdot23+\left|x-1\right|=2200\)
=>\(23\cdot\left(15-85\right)+\left|x-1\right|=2200\)
=>\(23\cdot\left(-70\right)+\left|x-1\right|=2200\)
=>\(\left|x-1\right|=2200+23\cdot70=3810\)
=>\(\left[{}\begin{matrix}x-1=3810\\x-1=-3810\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3811\\x=-3809\end{matrix}\right.\)
c: \(11-\left(-53+x\right)=97\)
=>\(11+53-x=97\)
=>64-x=97
=>x=64-97=-33
d: \(-\left|x-\left(-4\right)\right|=-9\)
=>\(\left|x-\left(-4\right)\right|=9\)
=>\(\left|x+4\right|=9\)
=>\(\left[{}\begin{matrix}x+4=9\\x+4=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-13\end{matrix}\right.\)
e: \(-\left(x+84\right)+213=-16\)
=>\(213-x-84=-16\)
=>\(129-x=-16\)
=>x=129+16=145
f: \(-\left(15-x\right)=2^5:2^3\)
=>\(x-15=2^2=4\)
=>x=4+15=19
`a, 461+(x-45)=387`
`<=> x-45=461-387`
`<=> x-45=74`
`<=> x=74+45=119`.
Vậy `x=119.`
`b, 15.23-85.23+|x-1|=2200`
`<=> 23.(15-85)+|x-1|=2200`
`<=> 23.(-60)+|x-1|=2200`
`<=> |x-1|=3580`
`<=> x=3581` hoặc `x=-3579.`