Tính
A = \(\frac{2^2.3^2.4^2...11^2}{6.10.15...78}\)
C = \(\frac{8^{20}+4^{20}}{4^{25}+6^{45}}\)
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Biết câu b
C=(2.4)^20+4^20/4^25+(4^3)^5
=2^20.4^20+4^20/4^25+4^15
=4^20.(2^20+1)/4^15.(4^10+1)
=4^20.(2^20+1)/4^15.(2^20+1)
=4^20/4^15=4^5=1024.
k giúp mk nha! Chúc bạn học tốt.
=\(\frac{2^{15}\cdot\left(3^2\right)^4}{2^6\cdot3^6.3^3}+\frac{\left(2^3\right)^2\cdot\left(2^2\right)^5}{2^{20}}\)
=\(\frac{2^9}{3}+\frac{1}{2^4}\)
=\(\frac{512}{3}+\frac{1}{16}=\frac{8192}{48}+\frac{3}{48}=\frac{8195}{48}\)
\(A=\frac{8^{10}+4^{10}}{8^4+4^{11}}\\ =\frac{8^4.8^6+4^{10}}{8^4+4^{10}.4}\\ =\frac{8^6}{4}\\ =\frac{262144}{4}\\ =65536\)
ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac
\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)
\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)
\(A=\frac{4-1}{36+12}\)
\(A=\frac{3}{48}=\frac{1}{16}\)
\(a.\frac{27.45+27.55}{2+4+6+...+14+16+18}=\frac{27.100}{\frac{\left(2+18\right).9}{2}}=30\)
\(b.\frac{26.108-26.12}{32-28+24-20+16-12+8-4}=\frac{26\left(108-12\right)}{\left(32-28\right).4}=\frac{26.96}{4.4}=156\)
\(c.\frac{27.4500+135.550.2}{2+4+6+...+14+16+18}=\frac{270.450+270.550}{\frac{\left(2+8\right).9}{2}}\)
\(d.\frac{48.700-24.45.20}{45-40+35-30+25-20+15-10+5}=\frac{48.700-48.450}{5.5}\)\(=\frac{48\left(700-450\right)}{25}=\frac{48.250}{25}=480\)
#ĐinhBa