6*(x+7)+2*(x+11)-5*x=83
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\(5+x-3=5-\left(x+4\right)\)
\(5+x-3=5-x-4\)
\(x+x=5-4-5+3\)
\(2x=-1\)
\(x=\frac{-1}{2}\)
vay \(x=\frac{-1}{2}\)
\(x-\left(5.\left|-7\right|+3\right)=\left|-8\right|+6-2\)
\(x-\left(5.7+3\right)=8+6-2\)
\(x-38=12\)
\(x=12+38\)
\(x=50\)
vay \(x=50\)
\(\left|x-3\right|+7=0\)
\(\left|x-3\right|=-7\)( ko ton tai)
\(12-3\left|x-1\right|=6\)
\(3\left|x-1\right|=6\)
\(\left|x-1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
vay \(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
8/3 . 2/5 . 3/8 . 10 .19/92 trên 5/7 . 5/11 +5/7 .2/11 - 5/7.11/11
=16/15 .15/4 .19/92 trên 5/7(5/11 +2/11 -11/11)
= .4 .19/92 trên 5/7.(-4/11)
=19/2 trên -20/77
\(\frac{\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}}{\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{11}{11}}\)
=\(\frac{\frac{2}{5}.10.\frac{19}{92}}{\frac{5}{7}.\left(\frac{5}{11}+\frac{2}{11}-1\right)}\)
=\(\frac{\frac{19}{23}}{\frac{-20}{77}}\)
=\(\frac{19}{23}.\frac{-77}{20}\)
=\(\frac{-1463}{460}\)
\(\left|2x+1\right|-x=5\)
\(\Rightarrow2x+1-x=5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=5-1\)
\(\Rightarrow x=4\)
118,24 - ( \(x\)x \(\frac{1}{5}\)+ \(x\)x 3 ) = 54,24
\(x\)x ( \(\frac{1}{5}\)+ 3 ) = 118,24 - 54,24
\(x\)x \(\frac{16}{5}\) = 64
\(x\) = 64 : \(\frac{16}{5}\)
\(x\) = 20
\(a.\dfrac{6}{7}-\dfrac{4}{21}=\dfrac{18-4}{21}=\dfrac{14}{21}=\dfrac{2}{3}\\ b.6\times\dfrac{12}{18}=\dfrac{6\times12}{18}=\dfrac{4}{1}=4\\ c.\dfrac{2}{5}\times\dfrac{3}{7}+\dfrac{2}{5}\times\dfrac{4}{7}-\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\times\dfrac{2}{5}=\dfrac{7}{7}\times\dfrac{2}{5}=1\times\dfrac{2}{5}=\dfrac{2}{5}\)
\(\dfrac{20\times25\times7\times8}{75\times8\times12\times14}\)
= \(\dfrac{4\times5\times25\times7\times8}{3\times25\times8\times3\times4\times2\times7}\)
= \(\dfrac{25\times7\times8\times4\times5}{25\times7\times8\times4\times2\times3\times3}\)
= \(\dfrac{25\times7\times8\times4}{25\times7\times8\times4}\) x \(\dfrac{5}{2\times3\times3}\)
= 1 x \(\dfrac{5}{18}\)
= \(\dfrac{5}{18}\)
\(=\dfrac{5.4.5.5.7.8}{5.3.5.8.7.4}\)
Triệt tiêu những phần giống nhau của cả tử và mẫu ta có:
\(=\dfrac{5}{3}\)
\(6\left(x+7\right)+2\left(x+11\right)-5x=83\)
\(\Leftrightarrow42+6x+22+2x-5x=83\)
\(\Leftrightarrow6x+2x-5x+\left(42+22\right)=83\)
\(\Leftrightarrow3x+64=83\)
\(\Leftrightarrow3x=83-64\)
\(\Leftrightarrow3x=19\)
\(\Leftrightarrow x=\frac{19}{3}\)
Vậy ...........