Câu 2 : tính
7-5/6×5
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\(7-\dfrac{5}{6}\times5\)
\(=7-\dfrac{25}{6}\)
\(=\dfrac{42}{6}-\dfrac{25}{6}\)
\(=\dfrac{17}{6}\)
Chúc bạn học tốt
a, \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) : 7 + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{1}{7}\) + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{6}{7}\) + \(\dfrac{1}{7}\)) + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) + \(\dfrac{6}{5}\)
= \(\dfrac{9}{5}\)
b, 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1212}{2424}\))
= 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\))
= 2018 \(\times\)1
= 2018
a) 3/5 x 6/7 + 3/5 x 1/7 + 6/5
3/5 x ( 6/7 + 1/7 ) + 6/5
3/5 x 7/7 + 6/5
3/5 x 1 + 6/5
3/5 + 6/5
9/5
b) 2018 x ( 1/2 + 1212/ 2424 )
2018 x ( 1/2 + 12/24 )
2018 x ( 1/2 + 1/2 )
2018 x 2/2
2018 x 1
2018
Học tốt
a) đáp án là 15/14 hoặc 1 1/4
b) đáp án là 27/5 hoặc 5 2/5. Hok tốt!!:)
Câu 1:
a. $3\frac{2}{3}+2\frac{1}{2}=(3+2)+(\frac{2}{3}+\frac{1}{2})=5+\frac{7}{6}=6+\frac{1}{6}=6\frac{1}{6}$
b. \(2\frac{1}{2}\times 3\frac{2}{5}=\frac{5}{2}\times \frac{17}{5}=\frac{17}{2}\)
c.
\(3\frac{1}{3}: 4\frac{1}{4}=\frac{10}{3}: \frac{17}{4}=\frac{40}{51}\)
d.
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=(3+4-5)+(\frac{1}{2}+\frac{5}{7}-\frac{5}{14})=2+\frac{6}{7}=2\frac{6}{7}\)
Câu 2:
a. $x\times \frac{2}{7}=\frac{6}{11}$
$x=\frac{6}{11}: \frac{2}{7}=\frac{21}{11}$
b. $x: \frac{3}{2}=\frac{1}{4}$
$x=\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$
Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
`@` `\text {Ans}`
`\downarrow`
`7-5/6 \times 5`
`= 7 - (5 \times 5)/6`
`= 7 - 25/6`
`= 17/6`
1/15