tìm x:
x-25%.x=\(\frac{1}{2}\)
You nào làm đúng mik sẽ tick
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\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\frac{1}{3}:\left(2x-1\right)=-5-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=-\frac{20}{4}-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=-\frac{21}{4}\)
\(\left(2x-1\right)=\frac{1}{3}:-\frac{21}{4}\)
\(\left(2x-1\right)=\frac{1}{3}.-\frac{4}{21}\)
\(\left(2x-1\right)=-\frac{4}{63}\)
2x= -4/63 + 1
2x = 59/63
x = 59/63 : 2
x = 59/126
1/3:(2.x-1)=-5-1/4
1/3:(2.x-1)=-21/4
2.x-1=1/3:-21/4
2.x-1=-4/63
2.x=-4/63+1
2.x=\(3\frac{59}{63}\)
x=\(3\frac{59}{63}\):2
x=\(1\frac{61}{63}\)
\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)
\(\Rightarrow\frac{5}{x}=\frac{1}{8}-\frac{y}{4}\)
\(\Rightarrow\frac{5}{x}=\frac{1-2y}{8}\)
\(\Rightarrow x\left(1-2y\right)=40\)
tu xet bang
tớ có cách khác:))
\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)
\(\Rightarrow\frac{20+xy}{4x}=\frac{1}{8}\)
\(\Rightarrow\frac{40+2xy}{8x}=\frac{x}{8x}\)
\(\Rightarrow40+2xy=x\)
\(\Rightarrow40=x\left(1-2y\right)\)
Cách này xem cho vui nha.dài hơn cách của Phương Uyên.
f(x)=9x3-1/3x+3x2-3x+1/3x2-1/9x3-3x2-9x+27+3x
= 9x3-1/9x3+3x2+1/3x2-3x2-1/3-3x-9x+3x+27
= 80/9x3+1/3x2-28/3x+27
---> \(x^2+3x+2-72=0\)
---> \(x^2+3x-70=0\)
---> \(x^2+10-7x-70=0\)
---> \(\left(x-7\right)\left(x+10\right)=0\)
---> \(\orbr{\begin{cases}x-7=0\\x+10=0\end{cases}}\)
---> \(\orbr{\begin{cases}x=7\\x=-10\end{cases}}\)
xin tiick
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x.2^3+2^x.1=144\)
\(\Rightarrow2^x.\left(2^3+1\right)=144\)
\(\Rightarrow2^x.9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
\(x-25\%.x=\frac{1}{2}\)
\(x.1-\frac{1}{4}.x=\frac{1}{2}\)
\(x.\left(1-\frac{1}{4}\right)=\frac{1}{2}\)
\(x.\left(\frac{4}{4}-\frac{1}{4}\right)=\frac{1}{2}\)
\(x.\frac{3}{4}=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{3}{4}\)
\(x=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
x-25%.x=1/2
=>75%x=1/2
=>3/4x=1/2
=>x=2/3