giúp nhanh !!!!
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xy-2y-x=11
x(y-1)-2y=11
x(y-1)-2y+2=13
x(y-1)-(2y-2)=13
x(y-1)-2(y-1)=13
(y-1)(x-2)=13
Đến đây dễ rồi, bạn tự làm nốt nhé
Mồ ~~~~~Hk giải nốt ik...Bn nghĩ mình thông minh lắm sao mà bắt mk tự giải nốt z???
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\(=11\cdot\dfrac{16}{55}\cdot\dfrac{15}{8}=\dfrac{11\cdot5}{55}\cdot\dfrac{16}{8}\cdot3=2\cdot3=6\)
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bữa sau bạn nhớ giải thích nữa nha chớ mình không biết tại sao ra đáp án đó đâu
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98200 - 5689 x 4 = 98200 - 22756 = 75444
80.000 + (5980 + 4700) = 80.000+75444=90680
10208 x 3 + 47654 = 30624 + 47654 = 78278
3986 + 4695 x 7 = 8681 x 7 = 60767
98200-5689\(\times\)4=98200-22756=75444
80000+(5980-4700)=80000+12801=92801
10208\(\times\)3+47654=30624+47654=78278
3986+4695\(\times\)7=3986+32865=36851
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a: -2x+5=0
=>2x=5
=.x=5/2
c: -x-3=0
=>x+3=0
=>x=-3
m: =>x(x-1)(x+1)=0
=>x=0;x=1;x=-1
b: =>8x^3=1
=>x^3=1/8
=>x=1/2
d: =>3x-2=0 hoặc 1-x=0
=>x=1 hoặc x=2/3
g: =>(x-2)(x+2)=0
=>x=2; x=-2
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a: Xét ΔBAD và ΔBHD có
BA=BH
\(\widehat{ABD}=\widehat{HBD}\)
BD chung
Do đó; ΔBAD=ΔBHD
Suy ra: \(\widehat{BAD}=\widehat{BHD}=90^0\)
hay DH⊥BC
b: \(\widehat{ABC}=180^0-110^0=70^0\)
nên \(\widehat{ABD}=35^0\)
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\(\dfrac{3\times8\times11}{33\times4}=\dfrac{3\times11\times4\times2}{3\times11\times4}=2\)
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mà bạn thi hả?
chỉ giúp nốt câu này tthui mà mấy câu này toàn kiến thức bạn hok rùi mà
Bài 15:
\(\dfrac{1}{1\times3\times7}\)+\(\dfrac{1}{3\times7\times9}\)+\(\dfrac{1}{7\times9\times13}\)+\(\dfrac{1}{9\times13\times15}\)+\(\dfrac{1}{13\times15\times19}\)
= \(\dfrac{1}{6}\).(\(\dfrac{6}{1\times3\times7}\)+\(\dfrac{6}{3\times7\times9}\)+\(\dfrac{6}{7\times9\times13}\)+\(\dfrac{6}{9\times13\times15}\)+\(\dfrac{6}{13\times15\times19}\))
=\(\dfrac{1}{6}\).(\(\dfrac{1}{1.3}\)-\(\dfrac{1}{3.7}\)+\(\dfrac{1}{3.7}\)-\(\dfrac{1}{7.9}\)+\(\dfrac{1}{7.9}\)-\(\dfrac{1}{9.13}\)+\(\dfrac{1}{9.13}\)-\(\dfrac{1}{13.15}\)+\(\dfrac{1}{13.15}\)-\(\dfrac{1}{15.19}\))
= \(\dfrac{1}{6}\).(\(\dfrac{1}{1.3}\) - \(\dfrac{1}{15.19}\))
= \(\dfrac{1}{6}\).(\(\dfrac{1}{3}\)-\(\dfrac{1}{285}\))
= \(\dfrac{1}{6}\).\(\dfrac{94}{285}\)
=\(\dfrac{47}{855}\)
Dấu chấm là dấu nhân em nhá
Bài 16:
2 - (\(\dfrac{1}{1\times5}\)+ \(\dfrac{1}{5\times9}\)+ \(\dfrac{1}{9\times13}\)+ \(\dfrac{1}{13\times17}\)+ \(\dfrac{1}{17\times21}\))
= 2 - \(\dfrac{1}{4}\) \(\times\)( \(\dfrac{4}{1\times5}\)+\(\dfrac{4}{5\times9}\)+\(\dfrac{4}{9\times13}\)+\(\dfrac{4}{13\times17}\)+\(\dfrac{1}{17\times21}\))
= 2 - \(\dfrac{1}{4}\)\(\times\)(\(\dfrac{1}{1}\)-\(\dfrac{1}{5}\)+\(\dfrac{1}{5}\)-\(\dfrac{1}{9}\)+\(\dfrac{1}{9}\)-\(\dfrac{1}{13}\)+\(\dfrac{1}{13}-\dfrac{1}{17}\)+\(\dfrac{1}{17}-\dfrac{1}{21}\))
= 2 - \(\dfrac{1}{4}\)\(\times\)(1- \(\dfrac{1}{21}\))
= 2 - \(\dfrac{1}{4}\)\(\times\)\(\dfrac{20}{21}\)
= 2 - \(\dfrac{5}{21}\)
= \(\dfrac{37}{21}\)