Tìm X biết: X% : 3 + 45% = 0,7
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(180-\left(x-45\right)\div2=120\)
\(\left(x-45\right)\div2=180-120\)
\(\left(x-45\right)\div2=60\)
\(x-45=60\times2\)
\(x-45=120\)
\(x=120+45\)
\(x=165\)
\(\left(2009-x\right)\div29+32=100\)
\(\left(2009-x\right)\div29=100-32\)
\(\left(2009-x\right)\div29=68\)
\(2009-x=68\times29\)
\(2009-x=1972\)
\(x=2009-1972\)
\(x=37\)
\(\left(x-2\right)\times3-270\div45=120\)
\(\left(x-2\right)\times3-6=120\)
\(\left(x-2\right)\times3=120+6\)
\(\left(x-2\right)\times3 =126\)
\(x-2=126\div3\)
\(x-2=42\)
\(x=42+2\)
\(x=44\)
\(\left(x+0,2\right)+\left(x+0,7\right)+\left(x+1,2\right)+...+\left(x+4,2\right)+\left(x+4,7\right)=65,5\)
\(\left(x+x+x+..+x+x\right)+\left(0,2+0,7+1,2+...+4,2+4,7\right)=65,5\)
\(10x+\frac{\left(0,2+4,7\right)\times10}{2}=65,5\)
\(10x+24,5=65,5\)
\(10x=65,5-24,5\)
\(10x=41\)
\(\Rightarrow x=4,1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`x-0,7<8`
`=>x<8,7`
Mà `8<x`
`=>8<x<8,7`
Nếu `x in ZZ=>x in` $\varnothing$
`x in R=>8<x<8,7`
Ta có: x-0.7<8<x
\(\Leftrightarrow x< 8.7\)
mà 8<x
nên 8<x<8,7
Vậy: S={x|8<x<8,7}
![](https://rs.olm.vn/images/avt/0.png?1311)
Từ 0,2 đến 4,7 có số số hạng là: \(\left(4,7-0,2\right):0,5+1=10\left(số\right)\)
⇒ Tổng 10 số đó là: \(\dfrac{\left(4,7+0,2\right)\cdot10}{2}=24,5\)
\(\left(x+0,2\right)+\left(x+0,7\right)+...+\left(x+4,7\right)=65,5\\ \Leftrightarrow10x+24,5=65,5\\ \Leftrightarrow10x=41\\ \Leftrightarrow x=4,1\)
Vậy x = 4,1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x\%:3+45\%=0,7\)
\(\Rightarrow x\%:3+0,45=0,7\)
\(\Rightarrow x\%:3=0,7-0,45\)
\(\Rightarrow x\%:3=0,25\)
\(\Rightarrow x\%=0,25.3\)
\(\Rightarrow x\%=0,75\)
\(\Rightarrow x\%=75\%\)
\(\Rightarrow x=75\)
Vậy \(x=75\)
\(x\%:3+45\%=0,7\)
\(\Rightarrow\frac{x}{300}+0,45=0,7\)
\(\Rightarrow x:300=0,25\)
\(\Rightarrow x=75\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=>|0,7-x|=-5,3+11 = 5,7
=> 0,7-x=5,7 hoặc 0,7-x=-5,7
=> x=-5 hoặc x=6,4
k mk nha
|0,7-x|= -5,3 + 11 = 5,6
\(\Rightarrow\orbr{\begin{cases}0,7-x=-5,6\\0,7-x=5,6\end{cases}\Rightarrow\orbr{\begin{cases}x=6,3\\x=4,9\end{cases}}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(5-\left(1+\dfrac{1}{3}\right):\left(1-\dfrac{1}{3}\right)\)
\(=5-\dfrac{4}{3}:\dfrac{2}{3}\)
\(=5-\dfrac{4}{3}\cdot\dfrac{3}{2}\)
\(=5-\dfrac{4}{2}\)
\(=5-2\)
\(=3\)
b) \(\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)-\left(1-\dfrac{5}{4}\right)+2022-\dfrac{2}{3}\)
\(=1+\dfrac{2}{3}-\dfrac{5}{4}-1+\dfrac{5}{4}++2022-\dfrac{2}{3}\)
\(=\left(1-1\right)+\left(\dfrac{2}{3}-\dfrac{2}{3}\right)+\left(-\dfrac{5}{4}+\dfrac{5}{4}\right)+2022\)
\(=0+0+0+2022\)
\(=2022\)
2) \(0,7^2\cdot x=0,49^2\)
\(\Rightarrow x=\dfrac{0,49^2}{0,7^2}\)
\(\Rightarrow x=\left(\dfrac{0,49}{0,7}\right)^2\)
\(\Rightarrow x=\left(0,7\right)^2\)
\(\Rightarrow x=0,49\)
b) \(x:\left(-0,5\right)^3=\left(0,5\right)^2\)
\(\Rightarrow x=\left(0,5\right)^2\cdot\left(-0,5\right)^3\)
\(\Rightarrow x=\left(-0,5\right)^5\)
\(\Rightarrow x=-\dfrac{1}{32}\)
2:
a: =>x*0,49=0,49^2
=>x=0,49
b: =>x=(0,5)^2*(-1)*(0,5)^3=-(0,5)^5
![](https://rs.olm.vn/images/avt/0.png?1311)
( x + 0,7 )3 = -27
( x + 0,7 )3 = (-3)3
=> x + 0,7 = -3
x = -3 -0,7
x = -3,7
Vậy x = -3,7
=))
\(\left(x+0,7\right)^3=-27\)
\(\Rightarrow\left(x+0,7\right)^3=\left(-3\right)^3\)
\(x+0,7=\left(-3\right)\)
\(x=\left(-3\right)-0,7\)
\(x=-3,7\)
Vậy \(x=-3,7\)
Chúc bạn học tốt !!!
\(X\%:3+45\%=0,7\\ \Leftrightarrow\dfrac{x}{100}:3+\dfrac{9}{20}=\dfrac{7}{10}\\ \Leftrightarrow\dfrac{x}{100}\times\dfrac{1}{3}=\dfrac{7}{10}-\dfrac{9}{20}\\ \Leftrightarrow\dfrac{x}{300}=\dfrac{14-9}{20}\\ \Leftrightarrow\dfrac{x}{300}=\dfrac{5}{20}\\ \Leftrightarrow x=\dfrac{300\times5}{20}=75\)
Vậy \(x=75\)