Tính:
A = 5/1.2 + 5/2.3 + 5/3.4 +...+ 5/99.100
(viết các bước làm ra cho mình nha)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\text{Ta có: }\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3.4}+.....+\frac{5}{99.100}\)
\(=5.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{99.100}\right)\)
\(=5.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{99}-\frac{1}{100}\right)\)
\(=5.\left(1-\frac{1}{100}\right)\)
\(=5.\frac{99}{100}\)
\(=\frac{99}{20}\)
5/1.2 + 5/2.3 + 5/3.4 + ... + 5/99.100
= 5 . ( 1/1.2 + 1/2.3 + 1/3.4 +... + 1/99.100 )
= 5 . ( 1 - 1/2 + 1/2 -1/3 + 1/3 - 1/4 + .... + 1/99 - 1/100 )
= 5 . ( 1 - 1/100 )
= 5 . 99/100
= 99/20
S=1.2+ 2.3+.......+99.100
Nhân cả 2 vế với 3, ta được:
3S=1.2.3+ 2.3.3+ 3.4.3+ 4.5.3+...... 99.100.3
= 1.2.3 + 2.3(4-1) + 3.4.(5-2) +...+ 99.100.(101-98)
= 1.2.3 + 2.3.4 -1.2.3 + 3.4.5-2.3.4 +...+ 99.100.101-98.99.100
= 99.100.101
----> S = (99.100.101):3
S = 333300
Vậy S=333300
\(=5\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right)\)
\(=5.\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)\)
\(=5\left(1-\dfrac{1}{100}\right)\)
\(=5.\dfrac{99}{100}=\dfrac{99}{20}\)
bạn hãy hãy cộng theo cặp cho dễ nhé,có 50 cặp như thế do đó là 101*50=5050
S=1.2+2.3+3.4+4.5+....+99.100
3S=1.2.3+2.3.3+3.4.3+4.5.3+....+99.100.3
3S=1.2.3+2.3.(4-1)+3.4.(5-1)+4.5(6-3)+....+99.100(101-98)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-2.4.5+....+99.100.101-98.99.100
3S=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+4.5.6-4.5.6+.......+99.100.101
3S=99.100.101
3S=999900
S=999900:3
S=333300
S=1.2+2.3+3.4+4.5+...+99.100
3S=1.2.3+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+99.100.(101-98)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100
3S=99.100.101
S=(99.100.101):3=333300
tính giá trị của biểu thức
C= 5/1.2 + 5/2.3 + 5/3.4 +...+ 5/99.100
giải chi tiết giùm mình
cảm ơn nhìu
C=5/1.2+5/2.3+5/3.4+...+5/99.100
C=5.(1/1.2+1/2.3+1/3.4+...+1/99.100)
C=5.(1-1/2+1/2-1/3+1/3-1/4+...+1/99-1/100)
C=5.(1-1/100)
C=5.99/100
C=99/20
K cho mik nha các bạn
\(C=5.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+......+\frac{1}{99.100}\right)\)
\(=5.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{99}-\frac{1}{100}\right)\)
\(=5.\left(1-\frac{1}{100}\right)\)
\(=5.\frac{99}{100}=\frac{495}{100}\)
\(A=5\left(\frac{1}{1.2}+\frac{1}{2.3}+.........+\frac{1}{99.100}\right)\)
\(=5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+............+\frac{1}{99}-\frac{1}{100}\right)\)
\(=5\left(1-\frac{1}{100}\right)\)
\(=5.\frac{99}{100}\)
\(=\frac{99}{20}\)
1. ta có :
\(3^2+4^2=5^{x-1}\)
\(25=5^{x-1}\)
\(5^2=5^{x-1}\)
=> x = 3
Ta có : S = 1.2 + 2.3 + 3.4 + ..... + 99.100
=> 3S = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 99.100.101
=> 3S = 99.100.101
=> S = 99.100.101/3
=> S = 333300
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3A=98.100.101
A=99.100.101 / 3
A=333300
Mình cho bạn dạng tổng quát nha
1.2+2.3+...+n.(n+1)=n(n+1)(n+2) / 3
3A=1.2.3+2.3.(4-1)+...........+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+............+99.100.101-98.99.100
3A=99.100.101
A=99.100.101:3
A=333300
A =\(\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3\cdot4}+...+\frac{5}{99.100}\)
A = 5 x (\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\) )
A = 5 x \(\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\right)\)
A = 5 x \(\left(1-\frac{1}{100}\right)\)
A = 5 x \(\frac{99}{100}\)
A = \(\frac{495}{100}\)
A= \(\frac{99}{20}\)
Ta co : A =5.(1/1.2+1/2.3+1/3.4+....+1/99.100)
A= 5.(1-1/2+1/2-1/3+1/3-1/4+.....+1/99-1/100)
Rut gon tung so ta co :A=5.(1-1/100)
A=5.99/100
A=1.99/50=99/50