tinh ket qua \(\sqrt{36}-\sqrt{144}+\sqrt{64}\)
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Tính:
a, √49 . √144+ √256 : √64
= 7 . 12 + 16 : 8
= 84 + 2
= 86
b, 72 : √2^2.36.3^2- √225
= 72: 2.6.3-15
= -13
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\(\sqrt{3}-\sqrt{27}-\sqrt{144}:\sqrt{36}\)
\(=\sqrt{3}-\sqrt{27}-2\)
\(=-2\sqrt{3}-2\)
\(=-2-2\sqrt{3}\)
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\(3\sqrt{144}-5\sqrt{49}+\dfrac{1}{2}\sqrt{36}\)
\(=3.12-5.7+\dfrac{1}{2}.6\)
\(=36-35+3=4\)
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Đặt \(A=\sqrt{x^2-6x+36}+\sqrt{x^2-6x+64}=18\)
\(B=\sqrt{x^2-6x+64}-\sqrt{x^2-6x+36}\)
\(\Rightarrow A.B=\left(x^2-6x+64\right)-\left(x^2-6x+36\right)=28\)
mà \(A=18\Rightarrow B=\frac{28}{18}=\frac{14}{9}\)
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\(A=2\sqrt{2}+3\sqrt{2}-4\sqrt{2}=\sqrt{2}\)
B=6+18-8=16
\(A=2\sqrt{2}+3\sqrt{2}-4\sqrt{2}=\sqrt{2}\\ B=2\cdot3+3\cdot6-8=6+18-8=16\)
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a)\(\sqrt{9.4}=\sqrt{36}=6;\sqrt{9}.\sqrt{4}=3.2=6\Rightarrow\sqrt{9.4}=\sqrt{9}.\sqrt{4}\)
b)\(\sqrt{169-144}=\sqrt{25}=5;\sqrt{169}-\sqrt{144}=13-12=1\Rightarrow\sqrt{169-144}>\sqrt{169}-\sqrt{144}\)
tra loi ho mik lun di mai ik hoc roi !chut chut chuit chut
= 6 - 12 + 8
= 14 - 12
= 2