39.(x-5)=39
(30-x).4=92
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L
4
13 tháng 9 2016
a) 39 . (x - 5 ) = 0
x - 5 = 0 : 39
x - 5 = 0
x = 0 + 5
x = 5
b) ( 30 - x ) . 4 = 92
30 . x = 92 : 4
30 . x = 23
x = 23 : 30
x =\(\frac{23}{30}\)
26 tháng 4 2022
a) 92 : 0,01 = 9200 92 x 100 = 9200 64 : 0,01= 6400
b) 25 : 0,5 = 50 25 x 2 = 50 39 : 0,5 = 78
c) 32 : 0,25 = 128 32 x 4 = 128 15 : 0,25 = 60
18 tháng 8 2020
a) (x - 78) .26 = 0 => x - 78 = 0 => x = 78
b) 39 (x - 5) = 39 => x - 5 = 1 => x = 6
c) (x - 14) : 2 = 3 => x - 14 = 6 => x = 20
d) (30 - x) . 4 = 92
=> 30 - x = 92 : 4
=> 30 - x = 23
=> x = 30 - 23 = 7
e) 45(91 - x) = 90
=> 91 - x = 90 : 45
=> 91 - x = 2
=> x = 91 - 2 = 89
f) (2x - 6)(3x - 18) = 0
=> \(\orbr{\begin{cases}2x-6=0\\3x-18=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=6\end{cases}}\)
g) 5x + 73.21 = 73.26
=> 5x = 73.26 - 73.21
=> 5x = 73(26 - 21) = 73.5
=> x = \(\frac{73\cdot5}{5}=73\)
h) 2x - 12 - x = 0
=> 2x - x - 12 = 0
=> x - 12 = 0
=> x = 12
NT
Tìm x biết:
a) ( x - 78 ) . 26 = 0 b) 39 . ( x - 5 ) = 39
c) ( x - 14 ) : 2 = 3 d) ( 30 - x ) : 4 = 92
2
20 tháng 6 2018
a) \(\left(x-78\right).26=0\) b) \(39.\left(x-5\right)=39\)
\(\left(x-78\right)=0\) \(x-5=39:39\)
\(x=0+78\) \(x=1+5\)
\(x=78\) \(x=6\)
P/S: Dấu "." là dấu nhân nhé
20 tháng 6 2018
\(\left(x-14\right):2=3\)
\(x-14=2.3\)
\(x=6+14\)
\(x=20\)
\(\left(30-x\right):4=92\)
\(30-x=92.4\)
\(30-x=368\)
\(x=30-368\)
\(x=-338\)
GL
2
TT
8 tháng 2 2021
\(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)
=> \(\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)
=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)
=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)
=> \(\left(x+100\right).\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)
=> x = - 100 (do \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)
8 tháng 2 2021
Ta có: \(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)
\(\Leftrightarrow\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)
\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)
\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)
mà \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)
nên x+100=0
hay x=-100
Vậy: S={-100}
24 tháng 1 2018
Ta có\(\frac{x+3}{97}+\frac{x+5}{95}+\frac{x+9}{91}=\frac{x+91}{9}+\frac{x+92}{8}+\frac{x+61}{39}\)
<=> \(\left(\frac{x+3}{97}+1\right)+\left(\frac{x+5}{95}+1\right)+\left(\frac{x+9}{91}+1\right)=\left(\frac{x+91}{9}+1\right)+\left(\frac{x+92}{8}+1\right)+\left(\frac{x+61}{39}+1\right)\)
<=>\(\frac{x+100}{97}+\frac{x+100}{95}+\frac{x+100}{91}=\frac{x+100}{9}+\frac{x+100}{8}+\frac{x+100}{39}\)
<=>\(\frac{x+100}{97}+\frac{x+100}{95}+\frac{x+100}{91}-\frac{x+100}{9}-\frac{x+100}{8}-\frac{x+100}{39}=0\)
<=> \(\left(x+100\right)\left(\frac{1}{97}+\frac{1}{95}+\frac{1}{91}-\frac{1}{9}-\frac{1}{8}-\frac{1}{39}\right)=0\)
Do \(\frac{1}{97}+\frac{1}{95}+\frac{1}{91}-\frac{1}{9}-\frac{1}{8}-\frac{1}{39}\ne0\)
Nên x+100=0 => x=-100
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 11 2023
8 ⋮ \(x\); 12 ⋮ \(x\); 24 ⋮ \(x\) ⇒ 8; 12; 24 ⋮ \(x\) ⇒ \(x\) \(\in\) ƯC(8;12;24)
8 = 23; 12 = 22.3; 24 = 22.3
ƯCLN(8; 12; 24) = 22 = 4
\(x\) \(\in\) {-4; -2; -1; 1; 2; 4}
15 tháng 9 2017
a) (x - 78) . 26 = 40
=>x-78 = 40 : 26 = 20/13
=> x = 78 + 20/13
=> x = 1034/13
b) 39 . (x-5) =39
=>x-5=39:39=1
=>x=1+5=6
c) 30- ( 52 - x) =90
=>30-52+x=90
=>-22+x=90
=>x=90-(-22)
=>x=112
d) (x-12) : 5 =2
=>x-12=2.5=10
=>x=10+12=22
a) 39.(x-5)=39
=> x-5=1
=> x=6
b) (30-x).4=92
=> 30-x=23
=> x=7
39.(x-5)=39
x-5=39:39
x-5=1
x=1+5
x=6
(30-x).4=92
30-x=92:4
30-x=18
x=30-18
x=12