tìm x thuộc số nguyên biết
x+1/27=x/9
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\(x-\dfrac{1}{8}=\dfrac{4}{x-2}\) hay \(x-\dfrac{1}{8}=\dfrac{4}{x}-2\) vậy bạn?
\(\Leftrightarrow xy=63\)
\(\Leftrightarrow\left(x,y\right)\in\left\{\left(1;63\right);\left(3;21\right);\left(7;9\right);\left(-63;-1\right);\left(-21;-3\right);\left(-9;-7\right)\right\}\)
\(\dfrac{x}{3}-\dfrac{1}{y+1}=\dfrac{1}{6}\)
=>\(\dfrac{xy+x-3}{3\left(y+1\right)}=\dfrac{1}{6}\)
=>\(2\left(xy+x-3\right)=1\)
=>2xy+2x-6=1
=>2xy+2x=7
=>2x(y+1)=7
=>x(y+1)=7/2
mà x,y nguyên
nên \(\left(x,y\right)\in\varnothing\)
1/y+1=x/3-1/6
1/y+1=2x/6-1/6
1/y+1= 2x-1/6
=> 1.6=(y+1).(2x-1)
ta có bảng
y+1 6 1
Past lives couldn't ever hold me down2x-1 1 6 ...
y 5 0
x 1 7/2
loại
\(x^{20}=x\\ \Leftrightarrow x^{20}-x=0\\ \Leftrightarrow x\left(x^{19}-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)
\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)
\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)
\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)
x + 1/27 = x/9
<=> 27x+1/27 = 3x/27
<=> 27x+1 = 3x
<=> 27x-3x= - 1
<=> 24x= -1
<=> x = -1/24