ƯCLN ( 60,90 ) =
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![](https://rs.olm.vn/images/avt/0.png?1311)
16=24;24=23.3
ƯCLN(16;24) =23=8; ƯC(16;24)={1;2;3;8}
180=22.32.5;234=2.32.13
ƯCLN(180;2340) =2.32=18; ƯC(180;234)={1;2;3;6;9;18}
60=22.3.5;90=2.32.5;135=33.5
ƯCLN(60;90;135)=3.5=15; ƯC(60;90;135)={1;3;5;15}
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a: UCLN(180;234)=18
UC(180;234)={1;2;3;6;9;18}
b: UCLN(60;80;176)=4
UC(60;80;176)={1;2;4}
![](https://rs.olm.vn/images/avt/0.png?1311)
60 = 22 . 5 . 3
90 = 2 . 32 . 5
⇒ BCNN(60,90) = 22 . 5 . 32 = 180
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có : \(Ư\left(16\right)=1;2;4;8;16\) và \(Ư\left(24\right)=1;2;3;4;6;8;12;24\)
\(\RightarrowƯC\left(16;24\right)=1;2;4;8\)
b, Ta có : \(\hept{\begin{cases}Ư\left(60\right)=1;2;3;4;5;6;10;12;15;20;20;60\\Ư\left(90\right)=1;2;3;5;6;9;10;15;18;30;45;90\end{cases}}\)
\(\RightarrowƯC\left(60;90\right)=1;2;3;5;6;15;30\)
c, Ta có : \(\hept{\begin{cases}Ư\left(18\right)=1;2;3;6;9;18\\Ư\left(30\right)=1;2;3;5;6;10;15;30\\Ư\left(42\right)=1;2;3;6;7;14;21;42\end{cases}}\)\(\RightarrowƯC\left(18;30;42\right)=1;2;3;6\)
d,Ta có : \(\hept{\begin{cases}Ư\left(26\right)=1;2;13;26\\Ư\left(39\right)=1;3;13;39\\Ư\left(48\right)=1;2;4;6;8;12;16;24;48\end{cases}}\)\(\RightarrowƯC\left(26;39;48\right)=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ƯCLN(33,55)=11
ƯCLN(48,90)=6
ƯCLN(105,210)=105
ƯCLN(48,60,120)=12
ƯCLN(45,60)=15
\(ƯCLN(33,55)\)
\(33 = 3.11\)
\(55 = 5.11\)
\(ƯCLN(33,55) = 11\)
\(ƯCLN(105,210)\)
\(105 = 5.3.7\)
\(210 = 2.5.3.7\)
\(ƯCLN(105,210) = 5.3.7 = 105\)
\(ƯCLN(48,90)\)
\(48 = 2^4.3\)
\(90 = 2.5.3^2\)
\(ƯCLN(48,90) = 3.2 = 6\)
\(ƯCLN(48,60,120)\)
\(48 = 2^4.3\)
\(60 = 2^2.3.5\)
\(120 = 2^3.3.5\)
\(ƯCLN(48,60,120) = 2^2.3 = 4.3 = 12\)
\(ƯCLN(45,60)\)
\(45 = 3^2.5\)
\(60 = 2^2.3.5\)
\(ƯCLN(45,60) = 3.5 = 15\)
là 15 đó bạn
60= 22 . 3 . 5
90= 2 . 32 . 5
ƯCLN (60,90)= 2 . 3 . 5 = 30
ĐÁP SỐ: 30