Nếu \(2^x=2\times16^{12}+2\times8^{16}\)thì giá trị của x là
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`(6xx8xx11)/(33xx16)`
`= (6xx8xx11)/(3xx11xx8xx2)`
`= 6/(3xx2)`
`=6/6=1`
`->A`
`(6xx8xx11)/(33xx16)`
`=(2xx3xx8)/(3xx16)`
`=(3xx16)/(3xx16)`
`=1`
`=>A`

thì giá trị của x là 4,\(\sqrt{x}\)=\(\sqrt{4}\)=2

`@` `\text {Ans}`
`\downarrow`
\(\text{ A = }\dfrac{1}{4\times8}+\dfrac{1}{8\times12}+\dfrac{1}{12\times16}+...+\dfrac{1}{172\times176}\)
\(\text{A = }\dfrac{1}{4}\times\left(\dfrac{4}{4\times8}+\dfrac{4}{12\times16}+...+\dfrac{4}{172\times176}\right)\)
\(\text{A = }\dfrac{1}{4}\times\left(\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{12}-\dfrac{1}{16}+...+\dfrac{1}{172}-\dfrac{1}{176}\right)\)
\(\text{A = }\dfrac{1}{4}\times\left(\dfrac{1}{4}-\dfrac{1}{176}\right)\)
\(\text{A = }\dfrac{1}{4}\times\dfrac{43}{176}\)
\(\text{A = }\dfrac{43}{704}\)
Đáp số: `\text {A =} 43/704.`

A = 1/4 x 8 + 1/8 x 12 + 1/12 x 16 + ... + 1/176 x 180
=> 4A = 4/4 x 8 + 4/8 x 12 + 4/12 x 16 + ... + 4/176 x 180
=> 4A = 1/4 - 1/8 + 1/8 - 1/12 + 1/12 - 1/16 + ... 1/176 - 1/180
=> 4A = 1/4 - 1/180
=> 4A = 45/180 - 1/180
=> 4A = 44/180
=> 4A = 11/45
=> A = 11/45 : 4
=> A = 11/180
Vậy A = 11/180
A = \(\dfrac{1}{4\times8}\) + \(\dfrac{1}{8\times12}\) + \(\dfrac{1}{12\times16}\) +...+ \(\dfrac{1}{176\times180}\)
A = \(\dfrac{1}{4}\) \(\times\)( \(\dfrac{4}{4\times8}\)+ \(\dfrac{4}{12\times16}\)+...+ \(\dfrac{4}{176\times180}\))
A = \(\dfrac{1}{4}\) \(\times\)( \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) + \(\dfrac{1}{12}\) - \(\dfrac{1}{16}\) +...+ \(\dfrac{1}{176}\) - \(\dfrac{1}{180}\))
A = \(\dfrac{1}{4}\) \(\times\)(\(\dfrac{1}{4}\) - \(\dfrac{1}{180}\))
A = \(\dfrac{1}{4}\) \(\times\)\(\dfrac{11}{45}\)
A = \(\dfrac{11}{180}\)

Ta có:
\(f\left(1\right)=0=1^3+a.1^2+b.1+c=a+b+c+1\Rightarrow a+b+c=-1\left(1\right)\)
\(f\left(2\right)=0=2^3+a.2^2+b.2+c=8+4a+2b+c\Rightarrow4a+2b+c=-8\left(2\right)\)
Lấy \(\left(2\right)-\left(1\right)\Rightarrow3a+b=-7\)
Mà ta có \(a+b=-16\Rightarrow2a-16=-7\Rightarrow2a=9\Rightarrow a=4,5\)

\(\dfrac{7}{8}-\dfrac{1}{4}\cdot\dfrac{5}{2}=\dfrac{x}{16}\)
=>\(\dfrac{x}{16}=\dfrac{7}{8}-\dfrac{5}{8}=\dfrac{2}{8}=\dfrac{1}{4}\)
=>\(x=\dfrac{16}{4}=4\)
=>Chọn A
\(2^x=2.16^{12}+2.8^{16}\)
\(2^x=2.\left(16^{12}+8^{16}\right)\)
\(2^x=2.\left(\left(2^4\right)^{12}+\left(2^3\right)^{16}\right)\)
\(2^x=2.\left(2^{48}+2^{48}\right)\)
\(2^x=2.2^{49}\)
\(2^x=2^{50}\)
\(\Rightarrow x=50\)
bằng 249