300:{180-[34+(15-3)^2]}
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d) Ta có: \(-8+\left(-14\right)+34+\left(-12\right)\)
\(=-8-14+34-12\)
\(=-20+20\)
\(=-0\)
e) Ta có: \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=\left(-7+57\right)+\left(-20-30\right)\)
\(=50-50=0\)
f) Ta có: \(300-\left(-180\right)-120-42\)
\(=300+180-120-42\)
\(=258+60=318\)
d, Ta có : \(\left(-8\right)+\left(-14\right)+34+\left(-12\right)\)
\(=-\left(8+12\right)+34-14=-20+20=0\)
e, Ta có : \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=-\left(30+20\right)+57-7=-50+50=0\)
f, Ta có : \(300-\left(-180\right)-120-42=318\)
\(180:\left\{300:\left[450-\left(4.5^3-2^2.25\right)\right]\right\}\\ =180:\left\{300:\left[450-\left(4.125-4.25\right)\right]\right\}\\ =180:\left\{300:\left[450-\left(500-100\right)\right]\right\}\\ =180:\left\{300:\left[450-400\right]\right\}\\ =180:\left\{300:50\right\}\\ =180:6\\ =30\)
\(180:\left\{300:\left[450-\left(4.5^3-2^2.25\right)\right]\right\}\\ =180:\left\{300:\left[450-\left(4.125-4.25\right)\right]\right\}\\ =180:\left\{300:\left[450-\left(4.100\right)\right]\right\}\\ =180:\left\{300:\left[450-400\right]\right\}\\ =180:\left\{300:50\right\}\\ =180:6\\ =30\)
180 : { 300 : [ 450 - ( 4 . 53 - 22 . 25 )]}
= 180 : { 300 : [ 450 - ( 4 . 125 - 4 . 25 )]}
= 180 : { 300 : [ 450 - ( 500 - 100 )]}
= 180 : { 300 : 50 }
= 180 : 6
= 30
180: ( 300: ( 450 - (4 x 53 - 22x 25)))
=180: ( 300: ( 450 - ( 500 - 100 )))
=180: ( 300: ( 450 - 400 ))
=180: ( 300: 50)
=180: 6 = 301) \(15^{40}=15^{4.10}=\left(15^4\right)^{10}=50625^{10}\)
\(18^{30}=18^{3.10}=\left(18^3\right)^{10}=5832^{10}\)
Vì \(50625^{10}>5832^{10}\) Nên \(15^{40}>18^{30}\)
2)\(180^{300}=180^{3.100}=\left(18^3\right)^{100}=5832^{100}\)
Vì \(2015^{100}<5832^{100}\) Nên \(2015^{100}<180^{300}\)
a) \(2^{24}< 3^{16}\)
b) \(3^{34}>5^{20}\)
c) \(\left(3\cdot24\right)^{100}< 3^{300}+4^{300}\)
d) \(199^{20}>200^{15}\)
a) 84
b) -300
c) 1700
a) = 10 . ( 7.8 )
= 10 . 56
= 560
b)
= 9.2.7.5
= ( 9.7 ) . ( 2.5 )
= 63 . 10
= 630
b) 7.x=42
x = 42 : 7
x = 6
c) 180 : x = -12
x = 180 : ( -12 )
x = -15
Bài 1:
a: Sửa đề: 1/3^200
1/2^300=(1/8)^100
1/3^200=(1/9)^100
mà 1/8>1/9
nên 1/2^300>1/3^200
b: 1/5^199>1/5^200=1/25^100
1/3^300=1/27^100
mà 25^100<27^100
nên 1/5^199>1/3^300
300 : { 180 - ( 34 + (15 -3)2 }
300 : { 180 - ( 34 + 144)}
300 : { 180 - 178}
300 : 2
= 150