2^7x9^2x2022^0/3^5x8^2
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b)
S2=6/2x5+6/5x8+6/8x11+...+6/29x32
=2.(3/2.5+3/5.8+...+3/29.32)
=2.(1/2-1/5+1/5-1/8+...+1/29-1/32)
=2.(1/2-1/32)
=2.15/32
=15/16
a)
Ta có:
S1=2/3x5+2/5x7+2/7x9+...+2/97x99
=1/3-1/5+1/5-1/7+...+1/97-1/99
=1/3-1/99
=32/99
b, Ta có : \(\frac{2^7x9^2}{3^3x2^5}=\frac{2^52^2x3^23.3}{3.3^2x2^5}=\frac{2^2x3}{x}=12\)
ta có \(2^7.9^2:3^3.2^5\)
=\(2^7.3^4:3^2.2^5\)
=\(\left(2^7.2^5\right):\left(3^4.3^3\right)\)
=\(2^{12}:3^7\)
=\(4096:2187\)=\(1,872885231\approx2\)
3/5 × 11/19 + 3/5 × 8/19 + 2/5
= 3/5 × (11/19 + 8/19) + 2/5
= 3/5 × 1 + 2/5
= 3/5 + 2/5
= 1
Ủng hộ mk nha ♡_♡
\(\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.87}\)
=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}+\frac{1}{19}-\frac{1}{32}+\frac{1}{32}-\frac{1}{57}+\frac{1}{57}-\frac{1}{87}\)
= 1/3 - 1/87
= 28/87
\(=\frac{1}{3.5}+\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{113.115}\right)\)
\(=\frac{1}{15}+\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{113}-\frac{1}{115}\right)\)
\(=\frac{1}{15}+\frac{1}{3}-\frac{1}{115}=\frac{9}{23}\)
27 x 92 x 20220/35 x 82
= 27 x 34 x 1/35 x 26
= 2/3