2/2×4+2/4×6+...+2/198×200=
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Khoảng cách = 2
Số số hạng là :
( 200 - 2 ) : 2 + 1 = 100 ( số )
Tổng là :
( 200 + 2 ) x 100 : 2 = 10100
Đáp số : 10100
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2 - 4 + 6 - 8 + .... + 198 - 200
\(=\underline{\left(-2\right)+\left(-2\right)+\left(-2\right)+....+\left(-2\right)}\)
50 số - 2
= ( - 2 ) . 50
= - 100
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Ta có: 2-4+6-8+...+198-200
= (-2) + (-2)+....+(-2)
= (-2) x 50
= -100
2-4+6-8+...+198-200=(-2)+(-2)+...+(-2) (có 50 số hạng -2)
=(-2).50= -100
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198-(x+4)=120
\(\Leftrightarrow\)198-x-4=120
\(\Leftrightarrow\)-x-4=-78
\(\Leftrightarrow\)-x=-74
\(\Leftrightarrow\)x=74
x+4= 198 - 120
x+4= 78
x= 78-4
x=74
Vậy x= 74
2x(x-51) = 2 x 2^3 + 20
2x( x-51) = 2 x 8+ 20
2x(x-51) = 16+20
2x- (x-51) = 36
2x-x+51= 36
x+ 51= 36
x= 51-36
=15
Vậy x=15
phần cuối làm giống phần đầu tiên, bn tự giải nha, nhớ k cho mk nhé!!!!^_^~~~~~~~~~~~~~~~~~~~
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C=(1-2-3-4)+(5-6-7-8)+...+(197-198-199-200)
=-8x50
=-400
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1+2-3-4+5+........................+197+198-199-200
=1+(2-3-4+5)+..........+(194-195-196+197)+(198-199-200)
=1+0+................+0+(-201)
=1+(-201)
=-200
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A = \(\dfrac{2}{2.4}\) + \(\dfrac{2}{4.6}\) + ....+ \(\dfrac{2}{198.200}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{6}\) + ......+ \(\dfrac{1}{198}\) - \(\dfrac{1}{200}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{200}\)
A = \(\dfrac{99}{200}\)