Tính hợp lí ( nếu có thể ): 2*(-4)^2+2*(-5)-20
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\(a.\left[-\dfrac{6}{11}.\dfrac{11}{-6}\right].\dfrac{7}{10}.\left(-20\right)=1.7.\left(-2\right)=-14\)
\(b.\dfrac{-1}{2}:\dfrac{3}{4}.\dfrac{-7}{2}=\dfrac{7}{4}:\dfrac{3}{4}=\dfrac{7}{3}\)
\(c.\dfrac{93}{7}:-\dfrac{8}{9}+\dfrac{19}{7}:\dfrac{-8}{9}=\left(\dfrac{93}{7}+\dfrac{19}{7}\right):-\dfrac{8}{9}=\dfrac{-9}{8}.\dfrac{112}{7}=-18\)
a) \(=\left(13\dfrac{2}{7}+2\dfrac{5}{7}\right):\left(-\dfrac{8}{9}\right)\)
\(=16:\dfrac{-8}{9}=\dfrac{-8\cdot\left(-2\right)\cdot9}{-8}=-18\)
b)
\(=\left(\dfrac{-6}{11}\cdot\dfrac{11}{-6}\right)\cdot\dfrac{7\cdot10\cdot\left(-2\right)}{10}\)
\(=-14\)
c) \(=\dfrac{-1}{2}\cdot\dfrac{4}{3}\cdot\dfrac{-7}{2}\)
\(=\dfrac{-1\cdot2\cdot2\cdot\left(-7\right)}{2\cdot3\cdot2}=\dfrac{7}{3}\)
5.(-8).2.(-3) = ( 5 . 2 ) . [ -8 . ( -3) ] = 10 . 24 = 240
5 . ( - 8 ) . 2 . ( - 3 )
= ( 5 . 2 ) . [ - 8 . ( - 3 ) ]
= 10 . 24
= 240
( 2020 - 7 + 3 ) - ( 7 + 3 - 2020 )
= 2020 - 7 + 3 - 7 - 3 + 2020
= ( 2020 + 2020 ) + ( 3 - 3 ) - ( 7 + 7 )
= 4040 + 0 - 14
= 4026
4.( - 5 )2 + 2. ( - 5 ) - 20
= 4. ( - 5 ) . ( - 5 ) + 2 . ( - 5 ) - 20
= ( - 5 ) . [ 4 . ( - 5 ) + 2 ] - 20
= ( - 5 ) . ( - 18 ) - 20
= 90 - 20 = 70
a)=(4.25).37
=100.37
=3700
b)=(132+868)+(763+237)+29
=1000+1000+29
=2029
c)=72+[131-1.20]
=49+[131-20]
=49+111
=160
2 . ( - 4 )2 + 2 . ( - 5 ) - 20
= 2 . 16 + 2 . ( - 5 ) - 20
= 2 ( 16 - 5 ) - 20
= 2 . 11 - 20
= 22 - 20
= 2