1045:[215-{3x-24}]=5 1045:[215-{3x-24}]=5
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\(5\cdot x+10\cdot9=990\)
\(\Rightarrow5\cdot x+90=990\)
\(\Rightarrow5\cdot x=900\)
\(\Rightarrow x=\dfrac{900}{5}\)
\(\Rightarrow x=180\)
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\(1045:\left[215-\left(3\cdot x-24\right)\right]=5\)
\(\Rightarrow215-\left(3\cdot x-24\right)=1045:5\)
\(\Rightarrow215-\left(3\cdot x-24\right)=209\)
\(\Rightarrow3\cdot x-24=215-209\)
\(\Rightarrow3\cdot x-24=6\)
\(\Rightarrow3\cdot x=30\)
\(\Rightarrow x=10\)
`@` `\text {Ans}`
`\downarrow`
`5.x + 10.9 = 990`
`\Rightarrow 5x + 90 = 990`
`\Rightarrow 5x = 990 - 90`
`\Rightarrow 5x = 900`
`\Rightarrow x = 900 \div 5`
`\Rightarrow x = 180`
Vậy, `x = 180`
\(1045 \div [ 215 - (3 . x - 24 ) ] = 5\)
`\Rightarrow 1045 \div (215 - 3x + 24) = 5`
`\Rightarrow 191 + 3x = 1045 \div 5`
`\Rightarrow 191 + 3x = 209`
`\Rightarrow 3x = 209 - 191`
`\Rightarrow 3x =18`
`\Rightarrow x = 18 \div 3`
`\Rightarrow x = 6`
Vậy, `x = 6.`
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\(a.\left[\left(x+34\right)-50\right].2=56\\ \Leftrightarrow\left(x+34\right)-50=28\\ \Leftrightarrow x+34=78\\ \Rightarrow x=44\)
\(b.1045-\left[215-\left(3x-24\right)\right]=5\\ \Leftrightarrow215-\left(3x-24\right)=1040\\ \Leftrightarrow3x-24=-825\\ \Leftrightarrow3x=-801\\ \Rightarrow x=-267\)
\(c.\left[195-\left(15x-27\right)\right].39=4212\\ \Leftrightarrow195-\left(15x-27\right)=108\\ \Leftrightarrow15x-27=87\\ \Leftrightarrow15x=114\\ \Rightarrow x=7,6\)
a) [(x+34)] - 50] . 2 = 56
=x+34-50=56:2
=> x+34-50=28
->x=28+50-34
-> x=44
b,1045 - [ 215 - ( 3x - 24 )] = 5
1045-(215-3x+24)=5
1045-215+3x-24=5
1045-215-24-5=-3x
-> 801=-3x-> x=801:(-3)=-267
,c) [ 195 - ( 15x - 27)] . 39 = 4212
(195-15x+27).39=4212
(195-15x+27)=4212/39=108
195+27-108=15x
114=15x-> x=114/15=7,6
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![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(1045:\left[215-\left(3x-24\right)\right]=5\)
\(\Rightarrow215-\left(3x-24\right)=1045:5\)
\(\Rightarrow215-\left(3x-24\right)=209\)
\(\Rightarrow3x-24=215-209\)
\(\Rightarrow3x-24=6\)
\(\Rightarrow3x=6+24\)
\(\Rightarrow3x=30\)
\(\Rightarrow x=30:3\)
\(\Rightarrow x=10\)
Vậy x = 10
b) \(\left[195-\left(15x+27\right)\right]\times39=4212\)
\(\Rightarrow195-\left(15x+27\right)=4212:39\)
\(\Rightarrow195-\left(15x+27\right)=108\)
\(\Rightarrow15x+27=195-108\)
\(\Rightarrow15x+27=87\)
\(\Rightarrow15x=87-27\)
\(\Rightarrow15x=60\)
\(\Rightarrow x=60:15\)
\(\Rightarrow x=4\)
Vậy x = 4
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![](https://rs.olm.vn/images/avt/0.png?1311)
a,91-5(5+x)=61
=>25+5x=91-61=30
=>5x=30-25=5
=>x=1
b,\([\left(x+34\right)-50]\)x2=56
=>(x+34)-50=56:2=28
=>x+34=28+50=78
=>x=78-34=44.
c,1045-\([2015-\left(3x-24\right)]\)=5
=>2015-(3x-24)=1045-5=1040
=>3x-24=2015-1040=975
=>3x=975+24=999
=>x=999:3=333
d,\([195-\left(3x-27\right)]\)x39=4212
=>195-(3x-27)=4212:39=108
=>3x-27=195-108=87
=>3x=87+27=117
=>x=39
e,30-3(x-2)=18
=>30-3x+6=18
=>30-3x=18-6=12
=>3x=30-12=18
=>x=18:3=6
a) \(...\Rightarrow5\left(5+x\right)=91-61=30\)
\(\Rightarrow\left(5+x\right)=30:5=6\Rightarrow x=6-5=1\)
b) \(...\Rightarrow\left(x+34\right)-50=56:2=28\)
\(\Rightarrow\left(x+34\right)=28+50=78\Rightarrow x=78-34=44\)
c) \(...\Rightarrow2015-\left(3x-24\right)=1045-5=1040\)
\(\Rightarrow\left(3x-24\right)=2015-1040=975\)
\(\Rightarrow3x=975+24=999\Rightarrow x=999:3=333\)
d) \(...\Rightarrow195-\left(3x-27\right)=4212:39=108\)
\(\Rightarrow\left(3x-27\right)=195-108=87\)
\(\Rightarrow3x=87+27=114\Rightarrow x=114:3=38\)
e) \(...\Rightarrow3\left(x-2\right)=30-18=12\Rightarrow x-2=12:3=4\)
\(\Rightarrow x=4+2=6\)
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1: \(=\dfrac{-5}{8}\cdot\dfrac{15}{4}=-\dfrac{75}{32}\)
2: \(=\dfrac{15}{17}\cdot\dfrac{25}{34}=\dfrac{375}{578}\)
3: \(=-12\cdot\dfrac{8}{3}=-4\cdot8=-32\)
4: \(=\dfrac{15}{14}\cdot\dfrac{20}{21}=\dfrac{50}{49}\)
5: \(=48\cdot\dfrac{24}{5}=230.4\)
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1. 36 x 25 x 4
= 36 x 100
= 3600
2. 18 x 24 : 9
= 18 : 9 x 24
= 2 x 24
= 48
3. 41 x 2 x 8 x 5
= 41 x 8 x 10
= 328 x 10
= 3280
4. 108 x (23+7)
= 108 x 30
= 3240
5. 215 x 86 + 215 x 14
= 215 x (86+14)
= 215 x 100
= 21500
6. 53 x 128 - 43 x 128
= (53-43) x 128
= 10 x 128
= 1280
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 :
\(A=26^2-24^2=\left(26-24\right)\left(26+24\right)=2.50=100\)
\(B=27^2-25^2=\left(27-25\right)\left(27+25\right)=2.52=104\)
Vì \(100< 104\Rightarrow A< B\)
Bài 2 :
\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)
\(\Rightarrow4\left(x^2+2x+1\right)+4x^2-4x+1-8\left(x^2-1\right)=11\)
\(\Rightarrow4x^2+8x+4+4x^2-4x+1-8x^2+8=11\)
\(\Rightarrow4x=-2\)\(\Leftrightarrow x=-\frac{1}{2}\)
1045:[215-{3x-24}]=5
1045 : [ 215 - { 3x - 24 }] = 5
215 - { 3x - 24 } = 1045 : 5
215 - { 3x - 24 } = 209
3x - 24 = 215 - 209
3x - 24 = 6
3x = 6 + 24
3x = 30
x = 30 : 3
x = 10