ét o ét
( 2/7 + 6/11 ) : x = 3/5
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\(-\dfrac{5}{6}\cdot\dfrac{7}{13}+\dfrac{19}{13}:\dfrac{6}{-5}+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\cdot\dfrac{7}{13}+\dfrac{19}{13}\cdot-\dfrac{5}{6}+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\left(\dfrac{7}{13}+\dfrac{9}{13}\right)+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\cdot2+\dfrac{2}{5}\)
\(=-\dfrac{5}{3}+\dfrac{2}{5}\)
\(=-\dfrac{25}{15}+\dfrac{6}{15}\)
\(=-\dfrac{19}{15}\)
#データネ
\(\dfrac{7}{5}x\dfrac{2}{5}=\dfrac{14}{25}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}x\dfrac{1}{2}=\dfrac{3}{4}+5x\dfrac{1}{2}=\dfrac{5}{2}\)
( 7 - \(x\))3 + (11 - 7)2 = 141
(7 - \(x\))3 + 42 = 141
( 7 - \(x\))3 + 16 = 141
(7 - \(x\))3 = 141 - 16
( 7 - \(x\))3 = 125
(7 - \(x\))3 = 53
7 - \(x\) = 5
\(x\) = 7 - 5
\(x\) = 2
\(\left(7-x\right)^3+\left(11-7\right)^2=141\)
\(\left(7-x\right)^3+4^2=141\)
\(\left(7-x\right)^3+16=141\)
\(\left(7-x\right)^3=141-16\)
\(\left(7-x\right)^3=125\)
\(\left(7-x\right)=5^3\)
\(\Rightarrow7-x=5\)
\(x=7-5\)
\(x=2\)
\(\text{Vậy x=2}\)
\(4,7\div0,25+5,3\times4\)
\(=18,8+21,2\)
\(=40\)
\(3\times\left(a-2\right)+150=240\)
\(3\times\left(a-2\right)=90\)
\(a-2=30\)
\(a=32\)
\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)
\(\dfrac{1}{9}+a=\dfrac{13}{36}\)
\(a=\dfrac{1}{4}\)
\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)
\(a=\dfrac{3}{2}\)
\(C=\dfrac{-1}{5}+\left(\dfrac{1}{-5}\right)^2+\left(-\dfrac{1}{5}\right)^3+...+\left(-\dfrac{1}{5}\right)^{99}\)
=>\(5\cdot C=-1+\left(-\dfrac{1}{5}\right)+\left(-\dfrac{1}{5}\right)^2+...+\left(-\dfrac{1}{5}\right)^{98}\)
=>\(5\cdot C-C=\left(-1\right)-\left(-\dfrac{1}{5}\right)^{99}\)
=>\(4C=-1+\dfrac{1}{5^{99}}=\dfrac{-5^{99}+1}{5^{99}}\)
=>\(C=\dfrac{-5^{99}+1}{4\cdot5^{99}}\)
(x-3y)^2006+(y+4)^2008=0
=>x-3y=0 và y+4=0
=>x=3y và y=-4
=>x=3*(-4)=-12 và y=-4
30 đơn vị, 5 phần mười, 8 phần trăm, 6 phần nghìn: 30,586
650 đơn vị, 9 phần trăm, 4 phần nghìn, 2 phần chục nghìn: 650,0942
7 đơn vị, 25 phần trăm, 9 phần nghìn 2 phần chục nghìn: 7,2592
15 đơn vị, 2 phần mười, 7 phần trăm, 3 phần triệu: 15,270003
\(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)
\(\Rightarrow-7x-189=6x+6\)
\(\Rightarrow-7x-6x=6+189\)
\(\Rightarrow-13x=195\)
\(\Rightarrow x=-15\)
Vay x = -15
( 2/7 + 6/11 ) : x = 3/5
64/77 : x = 3/5
x = 64/77 : 3/5
x = 320/231
( 2/7 + 6/11 ) : x = 3/5
64/77 : x = 3/5
x = 64/77 : 3/5
x = 64/77 x 5/3
x = 320/231