8abc chia abc =65 giúp mik vs
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\(8abc:abc=65\)
\(\left(8000+abc\right):abc=65\)
\(8000:abc+1=65\)
\(8000:abc=64\)
\(abc=125\)
Bài làm :
\(8abc:abc=65\)
\(\Leftrightarrow\left(8000+abc\right):abc=65\)
\(\Leftrightarrow8000:abc+1=65\)
\(\Leftrightarrow8000:abc=64\)
\(\Leftrightarrow abc=8000:64\)
\(\Leftrightarrow abc=125\)
Vậy abc = 125 .
Học tốt nhé
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25 x 34 + 65 x 75 - 35 x 86 + 65 x 45
= 5 x 17 x 10 + 65 x (75 + 45) - 7 x 43 x 10
= 85 x 10 + 780 x 10 - 301 x 10
= 10 x (85 + 780 - 301)
= 10 x 564
= 5640
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\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\)
\(\Leftrightarrow\dfrac{x+35}{65}+1+\dfrac{x+39}{61}+1=\dfrac{x+43}{57}+1+\dfrac{x+47}{53}+1\)
\(\Leftrightarrow\dfrac{x+100}{65}+\dfrac{x+100}{61}-\dfrac{x+100}{57}-\dfrac{x+100}{53}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\right)=0\Leftrightarrow x=-100\)
Ta có:
\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\\ \Rightarrow\left(\dfrac{x+35}{65}+1\right)+\left(\dfrac{x+39}{61}+1\right)=\left(\dfrac{x+43}{57}+1\right)+\left(\dfrac{x+47}{53}+1\right)\\ \Rightarrow\dfrac{x+100}{53}+\dfrac{x+100}{61}=\dfrac{x+100}{57}+\dfrac{x+100}{53}\\ \Rightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\right)=0\)
Ta thấy:
\(\dfrac{1}{65}< \dfrac{1}{57}\\ \dfrac{1}{61}< \dfrac{1}{53}\\ \Rightarrow\left(\dfrac{1}{65}+\dfrac{1}{62}\right)-\left(\dfrac{1}{57}+\dfrac{1}{53}\right)< 0\)
Hay \(\dfrac{1}{65}+\dfrac{1}{62}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\)
\(\Rightarrow x+100=0\\ \Rightarrow x=0-100\\ \Rightarrow x=-100\)
Vậy \(x=-100\)
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10³ + 2¹⁵
= 1000 + 32768
= 33768
Mà 33768 : 33 = 1023 (dư 9)
Em xem lại đề
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abc x 10 + 1 = 1000 + abc + 2489
abc x 10 + 1 = 3489 + abc
abc x 9 = 3489 - 1
abc x 9 = 3488
abc = 3488 : 9
2 ) tương tự
2) 8abc-abc8-abc8=3627
=> 8000+abc-abcx10+8-abcx10+8=3627
=> 8000+8+8-3627=abcx10+abcx10-abc
=> 4389=19abc
=> abc = 231
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2:
a: 45*12+180
45*12 chia hết cho 3
180 chia hết cho 3
=>45*12+180 chia hết cho 3
b: 37*4*16 không chia hết cho 3
24 chia hết cho 3
=>37*4*16-24 không chia hết cho 3
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Ta có :abc -cba=(100a+10b+c)-(100c+10b+a)
=100a+10b++a-100c-10b-a
=99a-99c
=9.(11a-11c) chia hết cho 9
Mặt khác : 99a-99c =11(9a-9c) chia hết cho 11
vậy hiệu của abc và cba chia hết cho 9 và 11
Ta có :
8abc : abc = 65
=> ( 8000 + abc ) : abc = 65
=> 8000 : abc + abc : abc = 65
=> 8000 : abc + 1 = 65
=> 8000 : abc = 64
=> abc = 8000 : 64 = 125
\(\overline{8abc}\) : \(\overline{abc}\) = 65
⇒ (8000 + \(\overline{abc}\) ) : \(\overline{abc}\) = 65
⇒ 8000 : \(\overline{abc}\) + \(\overline{abc}\) : \(\overline{abc}\) = 65
⇒ 8000 : \(\overline{abc}\) + 1 = 65
⇒ 8000 : \(\overline{abc}\) = 65 - 1
⇒ 8000 : \(\overline{abc}\) = 64
⇒ \(\overline{abc}\) = 8000 : 64
⇒ \(\overline{abc}\) = 125
vậy \(\overline{abc}\) = 125