120 : (193-17.10+7)
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Chọn P/S trung gian rồi đi so sánh
Mặc dù mk học rồi nhưng quên mất
Bạn thông cảm nhé
~~~~~ Chúc bạn học tốt ~~~~~~
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\(B=12.10^8+17.10^7+5.10^4+3\)
\(B=12.10^4.10^4+17.10^4.10^3+5.10^4+3\)
\(B=12.10000.10^4+17.1000.10^4+5.10^4+3\)
\(B=120000.10^4+17000.10^4+5.10^4+3\)
\(B=10^4\left(120000+17000+5\right)+3\)
\(B=10^4.137005+3\)
\(B=1370050000+3=1370050003\)
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a) A=6.10^7+5.10^5+4.10^3+2.10
A= 6.10000000+5.100000+4.1000+2.10
A= 60000000+500000+4000+20
A= 60504020
b) B=12.10^8+17.10^7+5.10^4+3
B= 12.100000000+17.10000000+5.10000+3
B=1200000000+170000000+50000+3
B=1370050003
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Bài làm
\(A=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right]\)
\(=\left[\frac{1}{386}.\frac{193}{17}+\frac{33}{34}\right]:\left[\frac{25}{4002}.\frac{2001}{25}+\frac{9}{2}\right]\)
\(=\left[\frac{1}{34}+\frac{33}{34}\right]:\left[\frac{1}{2}+\frac{9}{2}\right]\)
\(=\frac{1}{5}\)
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204+456=660
123-96=27
37+140=177
160-145=15
129-753= -624
789-298= 491
291+102= 393
183+290= 473
1,000-123= 877
810-723= 87
986+209= 1195
371-289= 82
730-368=362
260+719= 979
102+763= 865
123+456+7= 586
289-200= 89
120+385= 405
392-277= 115
193+240= 433
782+926= 1708
HỌC TỐT ><
Hí hí =))) Mình trả lời đầu tiên đấy =)))
204+456=660
123-96=27
37+140=177
160-145=15
129-753=-624
789-298=491
291+102=393
183+290=473
1,000-123=877
810-723=87
986+209=1195
371-289=82
730-368=362
260+719=979
102+763=865
123+456+7=586
289-200=89
120+385=505
392-277=115
193+240=433
782+926=1708
Chúc bạn hok tốt~~
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\(M=\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right)\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{2001}+\dfrac{11}{4002}\right)\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
\(M=\left[\left(\dfrac{4}{386}-\dfrac{3}{386}\right)\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{14}{4002}+\dfrac{11}{4002}\right)\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
\(M=\left(\dfrac{1}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right):\left(\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right)\)
\(M=\left(\dfrac{1}{34}+\dfrac{33}{34}\right):\left(\dfrac{1}{2}+\dfrac{9}{2}\right)\)
\(M=1:5\)
\(M=\dfrac{1}{5}\)
\(=\left[\dfrac{4-3}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
\(=\left(\dfrac{1}{34}+\dfrac{33}{34}\right):\left[\dfrac{1}{2}+\dfrac{9}{2}\right]\)
=1/5
120 : (193-17.10+7)
= 120 : ( 193 - 170 + 7 )
= 120 : ( 23 + 7 )
= 120 : 16
= 7,5
mk sửa lại chỗ này tí :
= 120 : 16
= 7,5
Sửa :
= 120 : 30
= 4
sorry