a=2005/2006+2006/2007+2007/2008+2008/2005
so sánh tổng a với 4
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta thấy:
2005/2006 = 1 - 1/2006
2006/2007 = 1 - 1/2007
2007/2008 = 1 - 1/2008
2008/2005 = 1 + 3/2005
Mà: 1/2005 > 1/2006 > 1/2007 > 1/2008
=> 3/2005 - 1/2006 - 1/2007 - 1/2008 > 0
=> 2005/2006 + 2006/2007 + 2007/2008 + 2008/2005 > 4
\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>\frac{2001}{2001}+\frac{2002}{2002}+\frac{2003}{2003}+\frac{2004}{2004}+\frac{2005}{2005}+\frac{2006}{2006}+\frac{2007}{2007}+\frac{2008}{2008}\)
\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>1+1+1+1+1+1+1+1\)\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>8\)
\(A>8\)
2005/2006 + 2006/2007 + 2007/2008 + 2008/2005
= 4,000001491
k minh di xin day
minh ko bietcach giai tra loi giup minh di ban minh can gap
2006/2007<1
2007/2008<1
2008<2009<1
2009/2006>1
A=2006/2007+2007/2008+2008/2009+2009/2006\(\approx\)3+1=4
\(A=\frac{2005}{2006}+\frac{2006}{2007}+\frac{2007}{2008}+\frac{2008}{2005}=1-\frac{1}{2006}+1-\frac{1}{2007}+1-\frac{1}{2008}+1+\frac{1}{2005}\)
\(=\left(1+1+1+1\right)+\left(\frac{1}{2005}-\frac{1}{2006}-\frac{1}{2007}-\frac{1}{2008}\right)<4+\left(\frac{3}{6015}-3.\frac{1}{2006}\right)\)
\(=4+\left(\frac{3}{6015}-\frac{3}{2006}\right)<4+\left(\frac{3}{2006}-\frac{3}{2006}\right)=4+0=4\)
=>đpcm