26-3{x+1}=17
ai giải hộ tôi đi
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2/3 x X = 31/4 + 1/4
2/3 x X = 8
x = 8 : 2/3
x = 12
kq x =12 nha
tick cho mk vs
\(x^2+2\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2=0\)
\(\Rightarrow x^2+2\left(x^2+2x+1\right)+3\left(x^2+4+4x\right)+4\left(x^2+6x+9\right)=0\)
\(\Rightarrow x^2+2x^2+4x+2+3x^2+12+12x+4x^2+24x+36=0\)
\(\Rightarrow10x^2+40x+50=0\)
\(\Rightarrow10\left(x^2+4x+5\right)=0\)
\(\Rightarrow x^2+4x+5=0\)
\(\Rightarrow\left(x^2+4x+2\right)+3=0\)
\(\Rightarrow\left(x+2\right)^2=-3\)
Mà \(\left(x+2\right)^2\ge0\)với mọi \(x\)
Vậy...
x + 6 = y(x - 1)
=> x + 6 = xy - y
=> x - xy + y = -6
=> x(1 - y) -1 + y = -7
=> x(1 - y) - (1 - y) = -7
=> (x - 1)(1 - y) = -7
tự xét bảng
b, tương tự
;x+6=y(x-1)
y ( x - 1 ) - x = 6
y ( x - 1 )- x + 1 = 7
y ( x - 1 ) - ( x x - 1 ) = 7
( y - 1 ) ( x - 1 ) = 7
a,(x+1)-(x+2)-(x+3)=24
=>x+1-x-2-x-3 =24
=>(x-x-x)+(1-2-3) =24
=> -x-4 =24
=> -x =24+4
=> -x =28
=> x =-28
Vậy x=-28
b,4x+2-3(x-1)=3x-5
=>4x+2-3x+3=3x-5
=>3x-4x+3x =2+3+5
=>2x =10
=>x =5
Vậy x=5
c,x-1-2(x-2)=x-11
=>x-1-2x+4=x-11
=>x-2x-x =-11+1-4
=>-2x =-14
=>x =7
Vậy x = 7
\(TH1:x-3\ge0\Rightarrow x\ge3\)
\(\Rightarrow x-3-3=-x\)
\(\Rightarrow x+x=3+3\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)( tm )
\(Th2:x-3< 0\Rightarrow x< 3\)
\(\Rightarrow-\left(x-3\right)-3=-x\)
\(\Rightarrow-x+3-3+x=0\)
\(\Rightarrow0x=0\)
\(\Rightarrow\)phương trình có vô số nghiệm
Vậy .........
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=\frac{1}{5}-x\)
\(\left(3x-5x\right)-\left(\frac{3}{2}+3\right)=\frac{1}{5}-x\)
\(\left(-2\right).x-\frac{9}{2}=\frac{1}{5}-x\)
\(\left(-2\right).x+x.1=\frac{1}{5}+\frac{9}{2}\)
\(-1.x=\frac{47}{10}\)
\(x=\frac{47}{10}:\left(-1\right)\)
\(x=\frac{47}{10}.\frac{1}{-1}\)
\(x=\frac{47}{-10}\)
Vậy \(x=\frac{47}{-10}\)
\(\frac{x}{12}=\frac{-3}{9}\)
\(\Rightarrow x=\frac{-3}{9}.12=-4\)
\(9.\left(\frac{1}{3}\right)^3+\frac{1}{3}\)
\(=9.\frac{1}{27}+\frac{1}{3}\)
\(=\frac{1}{3}+\frac{1}{3}\)
\(=\frac{2}{3}\)
9. \(\left(\frac{1}{3}\right)^3\)+\(\frac{1}{3}\)
=9. \(\frac{1}{9}\)+\(\frac{1}{3}\)
=1+\(\frac{1}{3}\)
\(1\frac{1}{3}=\frac{4}{3}\)
23 - 17 = x + 1
6 = x + 1
x = 6 - 1
x = 5
nhé !
3(x+1)=26-17=9
x+1=9:3=3
x=3-1
x=2