25*53 giup mk voi
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25-(4,45+x) = 13,8
4,45 + x = 25-13,8
4,45+x = 11,2
x = 11,2 - 4,45
x= 6,75
25-(4,45+x)=13,8
=> 4,45+x = 25 - 13,8
=> 4,45+x = 11,2
=> x = 11,2 - 4,45
=> x = 6,65
5-1 . 25n = 125
=> 5-1 . 52n = 53
=> -1 + 2n = 3
=> 2n = 4
=> n = 2
A=-41-25.|2-x|
nếu 2-x>=0<=>x<=2
thì |2-x|=2-x
=>A=-41-25.(2-x)=-41-50+25x=25x-91
nếu 2-x<0<=>x>2
thì |2-x|=x-2
=>A=-41-25.(x-2)
=-41-25x+50
=9-25x
vậy A=25x-91 khi x<=2
A=9-25x khi x>2
\(A=\frac{54.107-53}{53.107+54}=\frac{54.107+54-107}{\left(54-1\right).107+54}=\frac{54.\left(107+1\right)-107}{54.107-107+54}=\frac{54.108-107}{54.\left(107+1\right)-107}=\frac{54.108-107}{54.108-107}=1\)
\(B=\frac{135.296-133}{134.269+135}=\frac{135.296+135-268}{\left(135-1\right).269+135}=\frac{135.\left(296+1\right)-268}{135.269-269+135}=\frac{135.297-268}{135.\left(269+1\right)-269}=\frac{135.297-268}{135.270-269}>1\)
\(\Rightarrow A< B\)
\(A=\frac{54.107-53}{53.107+54}=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
\(B=\frac{135.296-133}{134.269+135}=\frac{134.296+296-133}{134.269+135}=\frac{134.296+163}{134.269+135}\)
Vì \(134=134;296>269\Rightarrow134.269< 134.296\)mà\(163>135\Rightarrow134.269+135< 134.296+163\)hay \(B>1\)
Ta có \(A=1;B>1\Rightarrow A< B\)
[53+(-76)]-[(-76)-(-53)]
=53+(-76)+76+(-53)
=[53+(-53)]+[(-76)+76]
=0+0=0
k cho mk nhé
Có A = 1998 x 2002
= (2000 - 2) x (2000 + 2)
= 20002 - 22
= 20002 - 4
Mà B = 2000 x 2000 = 20002 ; 20002 - 4 < 20002
=> A < B
Có B = 35 x 53 - 18
= (34 + 1) x 53 - 18
= 34 x 53 + 53 - 18
= 34 x 53 + 35
=> B = D
25 . 53 = 52 . 53 = 52 + 3 = 55
25 x 5^3 = 5^2 x 5^3 = 5^5 k minh nhá