Tìm x biết: (210 + 2x) : 212 = 2
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Bài làm
Sửa đề : \(\left(2x+3\right)-117=212\)( coppy lại đề nó vậy đấy, ko sao )
\(\Leftrightarrow2x+3=329\Leftrightarrow2x=326\Leftrightarrow x=163\)
(2x+ 3) - 117 = 212
=> 2x+ 3 = 212 + 171
2x+ 3 = 383
2x = 383 - 3
2x = 380
x = 380 : 2
x = 190
giúp mình nha
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6: =x^2-7xy+5xy-35y^2
=x(x-7y)+5y(x-7y)
=(x-7y)(x+5y)
7: =x^2-2xy-8xy+16y^2
=x(x-2y)-8y(x-2y)
=(x-2y)(x-8y)
8: =3x^2-6xy-4xy+8y^2
=3x(x-2y)-4y(x-2y)
=(x-2y)(3x-4y)
9: =4x^2+4xy+y^2-16y^2
=(2x+y)^2-16y^2
=(2x+y-4y)(2x+y+4y)
=(2x-3y)*(2x+5y)
10: =2(x^2+5xy+4y^2)
=2(x+y)(x+4y)
11: =5x(x+2y+y^2)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
= 2.(1+2+3+4+.....+x)=210
=1+2+3+4+........+x=210:2
=1+2+3+4+....+x=105
=(x+1).x:2=105
=(x+1).x=105.2
=(x+1).x=210
=(x+1).x=14.15
Vay x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
2+4+6+8+...+2x=210
=>2.1+2.2+2.3+2.4+...+2.x=210
=>2.(1+2+3+4+...+x)=210
=>1+2+3+4+...+x=210:2
=>1+2+3+4+...+x=105
=>x=14
2+4+6+8+...+2x=210
=>2.1+2.2+2.3+2.4+...+2.x=210
=>2.(1+2+3+4+...+x)=210
=>1+2+3+4+...+x=210:2
=>1+2+3+4+...+x=105
=>x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
2*(1+2+3+..+x)=210
2*(x+1)*x/2=210
(x+1)x=210
x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
2+4+6+...+2x=210
=2(1+2+3+...+x)=210
=1+2+3+...+x=105
=x+1.x/2=105
(x+1)x=210
14.15=210
=>x=14
Vậy x=14
210 + 2x = 21 x 212
210 + 2x = 213
2x = 213 : 210
2x = 23
x = 3