x^4+5x^3-14x^2-20x+16=0
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a) \(25x^2y-10xy+30xy^2=xy\left(25x+30y-10\right)\)
b) \(16x^2-20x=4x\left(4x-5\right)\)
c) \(18x^3+12x^2-30x=x\left(18x^2+12x-30\right)=x\left(x-1\right)\left(18x+9\right)=96x\left(x-1\right)\left(x+\dfrac{5}{3}\right)\)
d) \(14x\left(x+y\right)-4y\left(x+y\right)=\left(14x-4y\right)\left(x+y\right)\)
e) \(9x^3y^2+12xy^2+15x^2y^2=3xy^2\left(3x^2+5x+4\right)\)
f) \(x\left(x-3\right)-y\left(3-x\right)=x\left(x-3\right)+y\left(x-3\right)=\left(x+y\right)\left(x-3\right)\)
g) \(5x\left(x+4\right)-2y\left(4+x\right)=\left(x+4\right)\left(5x-2y\right)\)
a, \(16x^2-9\left(x+1\right)^2=0\)
\(\Leftrightarrow\left(4x\right)^2-\left(3x+3\right)^2=0\Leftrightarrow\left(4x-3x-3\right)\left(4x+2x+3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(6x+3\right)=0\Leftrightarrow x=-\frac{1}{2};x=3\)
b, \(\left(5x-4\right)^2-49x^2=0\Leftrightarrow\left(5x-4-7x\right)\left(5x-4+7x\right)=0\)
\(\Leftrightarrow\left(-2x-4\right)\left(12x-4\right)=0\Leftrightarrow x=-2;x=\frac{1}{3}\)
c, \(5x^3-20x=0\Leftrightarrow5x\left(x^2-4\right)=0\)
\(\Leftrightarrow5x\left(x-2\right)\left(x+2\right)=0\Leftrightarrow x=0;x=\pm2\)
1: Ta có: \(16x^2-9\left(x+1\right)^2=0\)
\(\Leftrightarrow\left(4x-3x-3\right)\left(4x+3x+3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(7x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{7}{3}\end{matrix}\right.\)
2: Ta có: \(\left(5x-4\right)^2-49x^2=0\)
\(\Leftrightarrow\left(5x-4-7x\right)\left(5x-4+7x\right)=0\)
\(\Leftrightarrow\left(2x+4\right)\left(12x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=\dfrac{1}{3}\end{matrix}\right.\)
3: Ta có: \(5x^3-20x=0\)
\(\Leftrightarrow5x\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
a) Thay x = 4 vào biểu thức A :
A = 45 - 5.44+ 5.43 - 5.42 + 5.4 -1
= 3
b) Thay x = 21 vào B :
B = 216 - 20.215 - 20.214 -20.213 - 20.212 - 20.21+3
=24
x^4 + 5x^3 - 14x^2 - 20x +16 = 0
<=> x4 + 6x3 - x3 - 4x2 - 6x2 - 4x2 + 4x - 24x + 16 = 0
<=> x4 + 6x3 - 4x2 - x3 - 6x2 + 4x - 4x2 - 24x + 16 = 0
<=> x2(x2 + 6x - 4) - x(x2 + 6x - 4) - 4(x2 + 6x - 4) = 0
<=> (x2 - x - 4)( x2 + 6x - 4 ) = 0
<=> x = (1 + √17)/2
<=> x = (1 - √17)/2
<=> x = -3+√13
<=> x = -3-√13