100.99-100.99
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a, tai x = 5 va y =2
x^2y +5xy^2 = 5^2 . 2 + 5 . 5 . 2^2 = 150
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(=\dfrac{1}{100}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)\)
\(=\dfrac{1}{100}-\dfrac{99}{100}=-\dfrac{49}{50}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=\(\frac{3}{100.99}-\frac{3}{99.98}-\frac{3}{98.97}-..-\frac{3}{3.2}-\frac{3}{2.1}\)
<=> \(\frac{1}{100.99}+\frac{1}{99.98}+\frac{1}{98.97}+...+\frac{1}{3.2}+\frac{1}{2.1}\)
\(=\frac{1}{2.1}-\frac{1}{3.2}+...+\frac{1}{98.97}+\frac{1}{99.98}+\frac{1}{100.99}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{97.98}+\frac{1}{98.99}+\frac{1}{99.100}\)
=\(\left(-\frac{1}{1}-\frac{1}{100}\right)=\frac{-99}{100}\)
Bạn nhớ thêm ngoặc vào đầu dòng và cuối dòng và thêm giấu âm vào đầu dòng mình quên thim
![](https://rs.olm.vn/images/avt/0.png?1311)
1/100.99 - 1/99.98 - 1/98.97 - ... - 1/3.2 - 1/2.1
= 1/100 - (1/100.99 - 1/99.98 - 1/98.97 - ... - 1/3.2 - 1/2.1)
= 1/100 - (1/1.2 + 1/2.3 + ... + 1/97.98 + 1/98.99 + 1/99.100)
= 1/100 - (1 - 1/2 + 1/2 - 1/3 + ... + 1/97 - 1/98 + 1/98 - 1/99 + 1/99 - 1/100)
= 1/100 - (1 - 1/100)
= 1/100 - 99/100
= -49/50
\(\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
\(=-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(=-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(=-\left(1-\frac{1}{100}\right)\)
\(=-\frac{99}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(100.99+100.98+100.97+100.96+100.95+10000\)
\(=100.99+100.98+100.97+100.96+100.95-100.100\)
\(=100\left(99+98+97+96+95-100\right)\)
\(=100.385\)
\(=38500\)
bằng 0 đó bạn
100.99-100.99
= 9900-9900
= 0