52/1*2+5/2*3+....+5/99*100
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Sửa đề: \(\dfrac{\dfrac{1}{1\cdot2}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}}{\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}}\)
\(=\dfrac{1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}}{\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}}\)
\(=\dfrac{\left(1+\dfrac{1}{3}+...+\dfrac{1}{99}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{100}\right)}{\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}}\)
\(=\dfrac{\left(1+\dfrac{1}{3}+...+\dfrac{1}{99}\right)+\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{100}\right)-2\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{100}\right)}{\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}}\)
=1



51/2* 52/2* ....*100/2 = [ 51*53*55*..*99 ]*[52*54*56*...*100]/2^50
= [ 51*53*55*..*99 ]*[26*27*28*...*50]*2^25/2^50
= [ 51*53*55*..*99 ]*[27**29*...*49]*[26*28*30*..50)/2^25
tiếp tục phân tích 26*28*30*..50 / 2^25 sẽ suy ra kết quả
hok tốt


Ta có:(1+1/3+1/5+...+1/99)-(1/2+1/4+1/6+...+1/100)
=(1+1/2+1/3+1/4+...+1/99+1/100)-2.(1/2+1/4+...+1/100)
=(1+1/2+1/3+1/4+...+1/99+1/100)-(1+1/2+1/3+...+1/50)
=1/51+1/52+...+1/99+1/100(đpcm)