\(\frac{1}{2}\)x 24 + \(\frac{1}{2}\)x 75 + \(\frac{1}{2}\)
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\(\Leftrightarrow\left(\dfrac{2}{3}x-1\right)^3\cdot\dfrac{1}{50}=\dfrac{75}{2}-24=\dfrac{27}{2}\)
\(\Leftrightarrow\left(\dfrac{2}{3}x-1\right)^3=\dfrac{27}{2}:\dfrac{1}{50}=675\)
\(\Leftrightarrow x\cdot\dfrac{2}{3}-1=3\sqrt[3]{25}\)
\(\Leftrightarrow x\cdot\dfrac{2}{3}=3\sqrt[3]{25}+1\)
\(\Leftrightarrow x=\dfrac{3\left(3\sqrt[3]{25}+1\right)}{2}\)
a) (x-1)2 =12:3
(x-1)2 =4
=> x-1=4 hoặc x-1=-4
1) x-1=4 2)x-1=-4
x=4+1 x=-4+1
x=5 x=-3
Vậy x thuộc {5;-3}
3/2-(43/8+X-75/24):50/3=1/2
3/2-(43/8+X-75/24)=25/3
43/8+X-75/24=-41/6
43/8+X=(-41/6)+75/24
43/8+X=(-85/24)
X=85/24-43/8
X=-109/12
Vậy X=-109/12
\(\frac{3}{2}-\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}\)\(=\frac{1}{2}\)
\(\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}=\frac{3}{2}-\frac{1}{2}\)
\(\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}=1\)
\(5\frac{3}{8}+x-\frac{75}{24}\)\(=1.16\frac{2}{3}\)
\(5\frac{3}{8}+x-\frac{75}{24}=\frac{50}{3}\)
\(5\frac{3}{8}+x=\frac{50}{3}+\frac{75}{24}\)
\(5\frac{3}{8}+x=\frac{475}{24}\)
\(x=\frac{475}{24}-5\frac{3}{8}\)
\(x=\frac{173}{12}\)
\(\frac{1}{2}\) x 24 + \(\frac{1}{2}\)x 75 + \(\frac{1}{2}\)
= \(\frac{1}{2}\) x 24 + \(\frac{1}{2}\)x 75 + \(\frac{1}{2}\) x 1
= \(\frac{1}{2}\)x ( 24 + 75 + 1 )
= \(\frac{1}{2}\) x 100
= 50
\(\frac{1}{2}\times24+\frac{1}{2}\times75+\frac{1}{2}\)
\(=\frac{1}{2}\times\left(24+75+1\right)\)
\(=\frac{1}{2}\times100\)
\(=50\)
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