P= x^2- 6xy +9y^2
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\(=\dfrac{4}{\left(x-3y\right)\left(x+3y\right)}\cdot\pm\left(2\sqrt{2}\right)\cdot y\cdot\left(x-3y\right)\)
\(=\dfrac{\pm8\sqrt{2}\cdot y}{x+3y}\)
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25 - x2 + 6xy - 9y2
= 25 - (x2 - 6xy + 9y2)
= 25 - (x2 - 6xy + 3y2)
= 52 - (x - 3)2
= [5 + (x - 3)] [5 - (x - 3)]
= (5 + x - 3) (5 - x + 3)
#Học tốt!!!
~NTTH~
25 - x2 + 6xy - 9y2
= 25 - (x2 - 6xy + 9y2)
= 25 - (x2 - 6xy + 3y2)
= 52 - (x - 3)2
= [5 + (x - 3)] [5 - (x - 3)]
= (5 + x - 3) (5 - x + 3)
#Học tốt!!!
~NTTH~
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\(\dfrac{x^2-9y^2}{x^2-6xy+9y^2}\) tại x = 1 , y = -\(\dfrac{2}{3}\)
= \(\dfrac{x^2-\left(3y\right)^2}{\left(x-3y\right)^2}\)
= \(\dfrac{\left(x-3y\right)\left(x+3y\right)}{\left(x-3y\right)}\)
= (x + 3y)
Thay x = 1 , y = -\(\dfrac{2}{3}\) vào
x + 3y
= 1 +3 . -\(\dfrac{2}{3}\)
= -1
Chúc bạn học tốt
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sorry, mk ko the giup dc taj vi nam nay mik len lop 7
P =(x - 3y)2
năm nay em cũng lên lop 7