Giải hộ vs
tìm x
\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
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Những câu hỏi liên quan
7 tháng 7 2019
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(\Leftrightarrow\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)
\(\Leftrightarrow\left(2x+\frac{3}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x+\frac{3}{5}=\frac{3}{5}\\2x+\frac{3}{5}=-\frac{3}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\2x=-\frac{6}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{3}{5}\end{cases}}\)
_Tần vũ_
7 tháng 7 2019
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(\Leftrightarrow3\left(3x-\frac{1}{2}\right)^3=-\frac{1}{9}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=-\frac{1}{27}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\left(-\frac{1}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(\Leftrightarrow3x=\frac{1}{6}\)
\(\Leftrightarrow x=\frac{1}{18}\)
_Tần Vũ_
L
15 tháng 9 2018
a) = \(12a^2b\left(a^2-b^2\right)\)
= \(12a^4b-12a^2b^3\)
b)nhân ra :
= \(2x^4-16x^3+4x^2-3x^3+24x^2-6x+5x^2-40x+10\)
= \(2x^4-19x^3+33x^2-46x+10\)
Tìm x:
a) \(\frac{1}{4}x^2-\left(\frac{1}{4}x^2-2x\right)=-14\)
= \(\frac{1}{4}x^2-\frac{1}{4}x^2+2x=-14\)
=\(2x=-14=>x=-7\)
b) \(x^3+27-x\left(x^2-1\right)=27\)
= \(x^3+27-x^3+x=27\)
= \(27+x=27=>x=0\)
24 tháng 7 2021
\(ĐKXĐ:x\ne2;x\ne-2;x\ne0\)
\(a,P=\left(\frac{-1}{2-x}-\frac{2x}{4-x^2}+\frac{1}{2+x}\right)\left(\frac{2}{x}-1\right)\)
\(P=\left(\frac{-2-x+2-x-2x}{\left(2-x\right)\left(2+x\right)}\right)\left(\frac{2-x}{x}\right)\)
\(P=\frac{-4x}{\left(2-x\right)\left(2+x\right)}\frac{2-x}{x}\)
\(P=\frac{-4}{2+x}\)
\(b,P=\frac{-4}{2+x}=\frac{1}{2}\)
\(2+x=-8\)
\(x=-10\)
\(c,P=-\frac{4}{2+x}\)
\(< =>-4⋮x+2\)
lập bảng ra thì bạn ra đc \(x=\left\{2;-1;-3;-6\right\}\)
AD
24 tháng 7 2021
a)\(P=\left(\frac{1}{x-2}-\frac{2x}{4-x^2}+\frac{1}{2+x}\right)\left(\frac{2}{x}-1\right)\)
\(P=\left(\frac{1}{x-2}+\frac{2x}{\left(x+2\right)\left(x-2\right)}+\frac{1}{2+x}\right).\frac{2-x}{x}\)
\(P=\frac{x+2+2x+x-2}{\left(x-2\right)\left(x+2\right)}.\frac{2-x}{x}\)
\(P=\frac{4x}{\left(x-2\right)\left(x+2\right)}.\frac{2-x}{x}\)
\(P=\frac{-4}{x+2}\)
b) Để P=1/2
\(\Rightarrow-\frac{4}{x+2}=\frac{1}{2}\)
\(\Leftrightarrow-8=x+2\)
\(\Leftrightarrow x=-10\)
c) Để P nhận GT nguyên
\(\Rightarrow\left(x+2\right)\inƯ_{\left(-4\right)}\)
\(\Rightarrow\left(x+2\right)\in\left\{-1;1;-2;2;-4;4\right\}\)
\(\Rightarrow x=\left\{-3;-1;-4;0;-6;2\right\}\)
#H
18 tháng 7 2016
a) \(\frac{2}{3}-\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5\)\(5\)
=> \(\frac{2}{3}-\left(\frac{1}{3}x-\frac{1}{2}\right)-\left(x+\frac{1}{2}\right)=5\)
=>\(\frac{2}{3}-\frac{1}{3}x+\frac{1}{2}-x-\frac{1}{2}=5\)
=>\(\left(\frac{2}{3}+\frac{1}{2}-\frac{1}{2}\right)-\left(\frac{1}{3}x+x\right)=5\)
=>\(\frac{2}{3}-\frac{4}{3}x=5\)
=>\(\frac{4}{3}x=\frac{2}{3}-5=-\frac{13}{3}\)
=>\(x=-\frac{13}{3}:\frac{4}{3}=-\frac{13}{4}\)
b)\(4x-\left(x+\frac{1}{2}\right)=2x-\left(\frac{1}{2}-5\right)\)
=>\(4x-x-\frac{1}{2}=2x-\left(-\frac{9}{2}\right)\)
=> \(3x-\frac{1}{2}=2x-\left(-\frac{9}{2}\right)\)
=>\(x=-\left(-\frac{9}{2}\right)+\frac{1}{2}=5\)
\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
\(=>2x+1-\frac{x}{3}=\frac{3}{2}:\left(-0,25\right)\)
\(=>\frac{5x}{3}+1=-6\)
\(=>\frac{5x}{3}=-7\)
\(=>5x=-21\)
\(=>x=-\frac{21}{5}\)
Ủng hộ nha
\(\Rightarrow2x+1-\frac{x}{3}=-6\Rightarrow2x+1-\frac{x}{3}+6=0\Rightarrow\frac{3.\left(2x+1\right)-x+6.3}{3}=0\)
\(\Rightarrow\frac{6x+3-x+18}{3}=0\Rightarrow5x+21=0\Rightarrow x=\frac{-21}{5}\)
Chúc e học tốt Chọn cho anh nha cảm ơn nhìu