7 phần 2 trừ 3 phần 2 x = 11 phần 2
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viết rõ lại cái đề giùm tui tui mới làm được
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Ta có : \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{5}{11}+\frac{19}{13}+\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\)
\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\right)\)
\(=1+1+2+1=5\)
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= (3/5 + 2/5) + (6/11 + 5/11) + (7/13 + 19/13) : 1/2 + 2/3 - 1/6
= (1 + 1 + 2) : (1/2 + 4/6 - 1/6)
= 4 : (1/2 + 1/2)
= 4 : 1
= 4
Vậy kết quả bằng 4
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1,
\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)
\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)
\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)
\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)
\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)
\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)
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\(\dfrac{7}{2}-\dfrac{3}{2}x=\dfrac{11}{2}\\ \dfrac{3}{2}x=\dfrac{7}{2}-\dfrac{11}{2}\\ \dfrac{3}{2}x=-2\\ x=-2:\dfrac{3}{2}\\ x=\dfrac{-4}{3}\)
\(\dfrac{7}{2} - \dfrac{3}{2}x = \dfrac{11}{2}\)
\( \dfrac{3}{2}x = \dfrac{7}{2} - \dfrac{11}{2}\)
\( \dfrac{3}{2}x = \dfrac{-4}{2}\)
\( \dfrac{3}{2}x = -2\)
\(x = -2 : \dfrac{3}{2}\)
\(x = -2 . \dfrac{2}{3} \)
\(x = \dfrac{-4}{3} \)
Vậy \(x = \dfrac{-4}{3} \)