( X - 140 ) : 7 = 27 - 8 x 3
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Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0
b) \(\left(x-140\right):7=27-24\)
\(\left(x-140\right):7=3\)
\(x-140=21\)
\(x=161\)
vay \(x=161\)
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-24:2:6-3=0\)
\(x-3-2-3=0\)
\(x-8=0\)
\(x=8\)
vay \(x=8\)
d) \(x+5.2-\left(32+16.3:6-15\right)=0\)
\(x+10-\left(32+8-15\right)=0\)
\(x+10-25=0\)
\(x-15=0\)
\(x=15\)
vay \(x=15\)
a) \(390-\left(x-8\right)=168:13\)
\(390-x+8=\frac{168}{13}\)
\(x+8=390-\frac{168}{13}\)
\(x+8=\frac{5070}{13}-\frac{168}{13}\)
\(x+8=\frac{4902}{13}\)
\(x=\frac{4902}{13}-8\)
\(x=\frac{4798}{13}\)
vay \(x=\frac{4798}{13}\)
137+4 (2x+3)=200(hình như đề bài sai)
200-6(x-5)=140
6(x-5)=200-140
6(x-5)=60
x-5=60:6
x-5=10
x=10+5
x=15
140:(x-8)=7
x-8=140:7
x-8=20
x=20+8
x=28
137+4(2x+3)=200
4(2x+3)=200-137
4(2x+3)=63
2x+3=63:4
2x+3=\(\frac{63}{4}\)
2x=\(\frac{63}{4}\)-3
2x=\(\frac{51}{4}\)
x=\(\frac{51}{4}\):2
x=\(\frac{51}{8}\)
Vậy ...
200-6(x-5)=140
6(x-5)=200-140
6(x-5)=60
x-5=60:6
x-5=10
x=15
Vậy...
140:(x-8)=7
x-8=140:7
x-8=20
x=20+8
x=28
Vậy...
k mik nhé
a , ( X - 140): 7 = 33 - 23 x 3
( X - 140): 7 = 27 - 8 x 3
( X - 140): 7 = 27 - 24
( X - 140): 7 = 3
( X - 140) = 3 x 7
( X - 140) = 21
X =140 +21
X = 161
1) 3/4 : x/6 = 75/100
x/6 = 3/4 : 75/100
x/6 = 1
x = 1*6
x = 6
Câu 6: Bạn xem ở đây: http://olm.vn/hoi-dap/question/615090.html
1.\(\frac{3}{4}:\frac{x}{6}=\frac{75}{100}\) \(\Leftrightarrow\frac{3}{4}.6.\frac{1}{x}=\frac{3}{4}\)
\(\Leftrightarrow\frac{6}{x}=1\)
\(\Leftrightarrow x=\frac{1}{6}\)
1, <=>33+x=45
<=> x = 12
Vậy x=12
2, <=>x+73 =102
<=> x =29
3,x=2
4, -23+x=25<=>x=2
6, x-8=20<=>x=28
a) \(5^x=100\)
\(5^x=10^2=\left(5\cdot2\right)^2\)
Sai đề
b) \(219-2^x=77\)
\(219-77=2^x\)
\(142=2^x\)??
c) \(18\left(x+27\right)=360\)
\(x+27=\frac{360}{18}=20\)
\(x=20-27=-7\)
d)\(\frac{\left(7x-140\right)}{21}=49\Rightarrow7x-140=49\cdot21=1029\)
\(7x=140+1029\)
\(7x=1169\Rightarrow x=\frac{1169}{7}=167\)
e) \(350+3^x=470\Rightarrow3^x=470-350=120\)
\(3^x=120????\)
Bài làm
a) \(\frac{x}{7}-\frac{3}{7}+\frac{1}{2}=\frac{31}{140}\)
\(\frac{x}{7}=\frac{31}{140}-\frac{1}{2}+\frac{3}{7}\)
\(\frac{x}{7}=\frac{31}{140}-\frac{70}{140}+\frac{60}{140}\)
\(\frac{x}{7}=\frac{21}{140}\)
\(\frac{x}{7}=\frac{3}{20}\)
=> \(x.20=3.7\)
=> \(x=\frac{3.7}{20}\)
=> \(x=\frac{21}{20}\)
Vậy \(x=\frac{21}{20}\)
b) \(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)
\(\frac{5}{x}=\frac{1}{2}+\frac{1}{8}-\frac{5}{12}\)
\(\frac{5}{x}=\frac{12}{24}+\frac{3}{24}-\frac{10}{24}\)
\(\frac{5}{x}=\frac{5}{24}\)
=> \(5.24=5.x\)
=> \(x=\frac{5.24}{5}\)
=> \(x=24\)
Vậy \(x=24\)
# Học tốt #
\(\left(x-140\right):7=27-8\times3\Rightarrow x=\left(27-24\right)\times7+140=161\)
Vậy x là 161
\(\left(x-140\right)\div7=27-8\times3\)
\(\Leftrightarrow\)\(\left(x-140\right)\div7=27-24\)
\(\Leftrightarrow\)\(\left(x-140\right)\div7=3\)
\(\Leftrightarrow\)\(\left(x-140\right)=3\times7\)
\(\Leftrightarrow\)\(x-140=21\)
\(\Leftrightarrow\)\(x=21+140\)
\(\Leftrightarrow\)\(x=161\)