33/49×121/5×3/22
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a: \(x-\dfrac{10}{3}=\dfrac{7}{15}\cdot\dfrac{3}{5}\)
=>\(x-\dfrac{10}{3}=\dfrac{21}{75}=\dfrac{7}{25}\)
=>\(x=\dfrac{7}{25}+\dfrac{10}{3}=\dfrac{21+250}{75}=\dfrac{271}{75}\)
b: \(x+\dfrac{3}{22}=\dfrac{27}{121}\cdot\dfrac{9}{11}\)
=>\(x+\dfrac{3}{22}=\dfrac{243}{1331}\)
=>\(x=\dfrac{243}{1331}-\dfrac{3}{22}=\dfrac{123}{2662}\)
c: \(\dfrac{8}{23}\cdot\dfrac{46}{24}-x=\dfrac{1}{3}\)
=>\(\dfrac{8}{24}\cdot\dfrac{46}{23}-x=\dfrac{1}{3}\)
=>\(\dfrac{2}{3}-x=\dfrac{1}{3}\)
=>\(x=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
d: \(1-x=\dfrac{49}{65}\cdot\dfrac{5}{7}\)
=>\(1-x=\dfrac{49}{7}\cdot\dfrac{5}{65}=\dfrac{7}{13}\)
=>\(x=1-\dfrac{7}{13}=\dfrac{6}{13}\)
\(\frac{2}{3}.x=\frac{1}{3}\)1) x-\(\frac{10}{3}\)=\(\frac{7}{15}.\frac{3}{5}\)
x-10/3=7/25
x=7/25+10/3
x=\(\frac{271}{75}\)
2)\(\frac{8}{23}.\frac{46}{24}.x=\frac{1}{3}\)
2/3.x=1/3
x=1/3:2/3
x=1/2
\(\dfrac{2}{49}\) x 121 : \(\dfrac{22}{7}\)
= \(\dfrac{2}{49}\) x 121 x \(\dfrac{7}{22}\)
= \(\dfrac{2}{7\times7}\) \(\times\)\(\dfrac{11\times11\times7}{11\times2}\)
= \(\dfrac{11}{7}\)
a, 43-121+18-x+49+11 = 37-51+28
=> -x= 14
=> x= -14 Vậy x=-14
b, 113-47-33+20=31-25-x+5
=> 53= 11-x
=>x=11-53=-42. Vậy x= -42
giải
a) ( 43-121+18) - ( X-49 -11)= 37- (51-28)
-60 - X + 60 = 37 - 23
-X = 14 => X= -14
b) 113-(47+33-20)=(31-25)-(X+5)
113 - 60 = 9 - X - 5
53 = 4 - X
53 - 4 = - X
49 = -X => X= -49
\(=\dfrac{32}{21}\cdot\dfrac{22}{16}\cdot\dfrac{49}{45}\cdot\dfrac{5}{11}\)
\(=\dfrac{32}{16}\cdot\dfrac{22}{21}\cdot\dfrac{5}{11}\cdot\dfrac{49}{45}\)
\(=2\cdot\dfrac{49}{45}\cdot\dfrac{22}{11}\cdot\dfrac{5}{21}\)
\(=4\cdot\dfrac{49}{21}\cdot\dfrac{5}{45}=4\cdot\dfrac{1}{9}\cdot\dfrac{7}{3}=\dfrac{28}{27}\)
\(\dfrac{32}{21}\times\dfrac{49}{45}:\dfrac{16}{22}\times\dfrac{15}{33}\)
\(=\dfrac{32}{21}\times\dfrac{49}{35}\times\dfrac{22}{16}\times\dfrac{15}{33}\)
\(=\dfrac{2\times16\times7\times7\times2\times11\times3\times5}{3\times7\times5\times7\times16\times3\times11}\)
\(=\dfrac{2\times2}{3}\)
\(=\dfrac{4}{3}\)
a: \(2\left(x-51\right)=2\cdot2^3+20\)
=>\(2\left(x-51\right)=2^4+20=36\)
=>x-51=36/2=18
=>x=18+51=69
b: \(2x-49=5\cdot3^2\)
=>\(2x-49=5\cdot9=45\)
=>2x=45+49=94
=>x=94/2=47
c: \(\left[\left(8x-12\right):4\right]\cdot3^3=3^6\)
=>\(\left[4\cdot\dfrac{\left(2x-3\right)}{4}\right]=3^3\)
=>\(2x-3=3^3=27\)
=>2x=3+27=30
=>x=30/2=15
d: \(2^{x+1}-2^2=32\)
=>\(2^{x+1}=32+2^2=32+4=36\)
=>\(x+1=log_236\)
=>\(x=log_236-1\)
e: \(\left(x^3-77\right):4=5\)
=>\(x^3-77=20\)
=>\(x^3=77+20=97\)
=>\(x=\sqrt[3]{97}\)
Gọi tập hợp số cần tìm là x
A = ( x thuộc N , x thuộc 2k+1 , 0 < x < 50 )
B = ( x thuộc N* , x thuộc Bội(11) , 10 < x < 100 )
33/49x121/5x3/22=1089/490
1089/490