1/1*2+1/2*3+1/3*4+...+1/13*14
Giải chi tiết vào nhé
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(x:\dfrac{1}{7}=\dfrac{1}{4}\\ \Rightarrow x=\dfrac{1}{4}.\dfrac{1}{7}\\ \Rightarrow x=\dfrac{1.1}{4.7}\\ \Rightarrow x=\dfrac{1}{28}\)
\(\frac{3}{5}-\frac{-7}{10}-\frac{13}{-20}=\frac{3}{5}+\frac{7}{10}+\frac{13}{20}=\frac{12}{20}+\frac{14}{20}+\frac{13}{20}=\frac{39}{20}\)
\(\frac{1}{2}+\frac{-1}{3}+\frac{1}{4}-\frac{-1}{6}=\frac{1}{2}+\frac{-1}{3}+\frac{1}{4}+\frac{1}{6}=\frac{6+(-4)+3+2}{12}=\frac{7}{12}\)
\(\frac{9}{4}.\frac{8}{27}.\frac{5}{7}=\frac{9.8.5}{4.27.7}=\frac{1.2.5}{1.3.7}=\frac{10}{21}\)
\(\frac{2}{5}.(\frac{2}{3}-\frac{1}{4})+\frac{1}{2}=\frac{2}{5}.(\frac{8}{12}-\frac{3}{12})+\frac{1}{2}=\frac{2}{5}.\frac{5}{12}+\frac{1}{2}=\frac{1}{6}+\frac{1}{2}=\frac{1}{6}+\frac{3}{6}=\frac{4}{6}=\frac{2}{3}\)
\((\frac{1}{3}-\frac{1}{6}):(\frac{1}{3}+\frac{1}{6})=(\frac{2}{6}-\frac{1}{6}):(\frac{2}{6}+\frac{1}{6})=\frac{1}{6}:\frac{3}{6}=\frac{1}{6}.\frac{6}{3}=\frac{1.6}{6.3}=\frac{1.1}{1.3}=\frac{1}{3}\)
Hok tốt
=>1/4:(x-2/3)=2
=>(x-2/3)=1/8
=>x=1/8+2/3=3/24+16/24=19/24
13/4 - 1/4 : ( x - 2/3 )= 5/4
\(\Rightarrow\) 1/4 : ( x- 2/3 ) = 13/4 - 5/4
\(\Rightarrow\) 1/4 : ( x- 2/3)= 2
\(\Rightarrow\) x - 2/3 = 1/4 :2
\(\Rightarrow\) x- 2/3 = 1/8
\(\Rightarrow\) x= 1/8 +2/3 =19/24
Vậy x = 19/24
\(A=\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}\)
\(A=\frac{1}{\left(1+2\right).2:2}+\frac{1}{\left(1+3\right).3:2}+\frac{1}{\left(1+4\right).4:2}+\frac{1}{\left(1+5\right).5:2}\)
\(A=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}\)
\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{6}\right)\)
\(A=2.\frac{1}{3}=\frac{2}{3}\)
0,75 \(\times\) \(\dfrac{4}{3}\) + \(\dfrac{5}{13}\) : \(\dfrac{1}{26}\)
= \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{3}\) + \(\dfrac{5}{13}\) \(\times\) \(\dfrac{26}{1}\)
= 1 + 10
= 11
a: \(=1-\dfrac{7}{10}=\dfrac{3}{10}\)
b: \(=\dfrac{42}{36}+\dfrac{15}{36}-\dfrac{2}{36}-\dfrac{36}{36}=\dfrac{19}{36}\)
c: \(=\dfrac{144}{48}+\dfrac{132}{48}-\dfrac{4}{48}-\dfrac{9}{48}=\dfrac{263}{48}\)
Đặt A=1/1*2+1/2*3+...+1/13*14
=> A=1-1/2+1/2-1/3+...+1/13-1/14
=> A=1-1/14
=> A=13/14