tìm x bt: 3/8=x/40A. x=15...B.x=5c.x=9d.x=12
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a) \(\frac{5}{12}=\frac{x}{72}\)
\(\Rightarrow5\cdot72=12\cdot x\)
\(\Rightarrow360=12\cdot x\)
\(\Rightarrow x=\frac{360}{12}=30\)
b) \(\frac{x+3}{15}=\frac{-1}{3}\)
\(\Rightarrow\left(x+3\right)\cdot3=15\cdot\left(-1\right)\)
\(\Rightarrow\left(x+3\right)\cdot3=-15\)
\(\Rightarrow x+3=-15:3=-5\)
\(\Rightarrow x=-5-3=-8\)
a) 5/12 = x /72
Vì 5. 72 = 12 .x
=> x = 5 .72 : 12
=> x = 30
b) x + 3/ 15 = -1/3
Vì ( x+3). 3 = 15. (-1)
=> x +3 = 15.( -1) : 3
=> x +3 = - 5
=> x = -5 - 3
=> x = -8
a) \(\frac{7}{13}x\frac{7}{15}-\frac{5}{12}x\frac{21}{39}+\frac{49}{91}x\frac{8}{15}=\frac{7}{13}x\frac{7}{15}-\frac{5}{12}x\frac{7}{13}+\frac{7}{13}x\frac{8}{15}\)
\(=\frac{7}{13}x\left(\frac{7}{15}-\frac{5}{12}+\frac{8}{15}\right)=\frac{7}{13}x\left(1-\frac{5}{12}\right)=\frac{7}{13}x\frac{7}{12}=\frac{49}{156}\)
b) \(\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)x\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)x0=0\)
Bài 2:
a) \(0,5+\left(x-\frac{15}{2}\right):\frac{1}{2}=\frac{9}{2}\)
\(\left(x-\frac{15}{2}\right):\frac{1}{2}=4\)
\(x-\frac{15}{2}=2\)
x = 19/2
b) \(2012\times x-2010\times x=2014\)
\(x\times\left(2012-2010\right)=2014\)
\(x\times2=2014\)
x = 1007
c) ( x + 1) + (x+2) + (x+3)+...+(x+100) = 5750
\(x\times100+\left(1+2+3+...+100\right)=5750\)
\(x\times100+5050=5750\)
\(x\times100=700\)
x = 7
a) \(x-\frac{3}{4}=\frac{15}{20}=\frac{3}{4}\)
\(x=\frac{3}{4}+\frac{3}{4}=\frac{6}{4}=\frac{3}{2}\)
b) \(\frac{x}{9}=\frac{4}{x}\Rightarrow x^2=36=6=-6\)
\(\Rightarrow x=\hept{\begin{cases}6\\-6\end{cases}}\)
a) \(x-\frac{3}{4}=\frac{15}{20}\)
\(\Rightarrow x=\frac{15}{20}+\frac{3}{4}\)
\(\Rightarrow x=\frac{3}{2}\)
b) \(\frac{x}{9}=\frac{4}{x}\)
\(\Rightarrow x^2=36\)
\(\Rightarrow x=6\)
Bạn viết lại đề đi, khó hiểu quá
mk đăng hộ bạn mk nên ko bt
xin lỗi nha