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1−199 x 1 − 1100....1−120061-199 � 1 - 1100....1-12006
=(9999−1999999-199)x(100100−1100100100-1100)....(20062006−1200620062006-12006) = 9899x99100....20052006=982006
NÈ EM
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\(S=6^2\left(1^2+2^2+3^2+...+10^2\right)=36.385=13860\)
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Tuoi bo la
( 54 + 28 ) : 2 = 41 ( tuoi )
Tong so tuoi cua hai chi em la
54 - 41 = 13 ( tuoi )
Tuoi em la
( 13 - 5 ) : 2 = 4 ( tuoi )
Tuoi toi la
13 - 4 = 9 ( tuoi )
Tuổi bố là : ( 54 + 28 ) : 2 = 41 ( tuổi )
Tuổi em và tôi là : 54 - 41 = 13 ( tuổi )
Tuổi tôi là : ( 13 + 5 ) : 2 = 9 ( tuổi )
Tuổi em là : 13 - 9 = 4 ( tuổi )
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.When did you start learning English ?
=> How long have you started learning English?
#Học Tốt :>
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\(1,\Leftrightarrow x^2-3x-4x+12=0\\ \Leftrightarrow\left(x-3\right)\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\\ 2,\Leftrightarrow4\left(x-3\right)+40=5x\\ \Leftrightarrow4x+28=5x\Leftrightarrow x=28\)
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Lời giải:
ĐKXĐ: $x\neq 0$
$A=\frac{2x^2}{2x^2-x}=\frac{2x}{2x-1}=\frac{2x-1+1}{2x-1}=1+\frac{1}{2x-1}$
Để $A$ nguyên thì $\frac{1}{2x-1}$ nguyên
$\Rightarrow 2x-1\in Ư(1)$
$\Rightarrow 2x-1\in \left\{1; -1\right\}$
$\Rightarrow x\in \left\{1; 0\right\}$
Vì $x\neq 0$ nên $x=1$ là kết quả duy nhất.
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\(a,5\left(x-3\right)-4=2\left(x-1\right)\\ =>5x-15-4=2x-2\\ =>5x-15-4-2x+2=0\\ =>3x-17=0\\ =>3x=17\\ =>x=\dfrac{17}{3}\)
\(b,x^2-x-6=0\\ =>x^2+2x-3x-6=0\\ =>x\left(x+2\right)-3\left(x+2\right)=0\\ =>\left(x-3\right)\left(x+2\right)=0\\ =>x=3;x=-2\)
c, đk : x khác -3 ; 3
\(\Rightarrow x^2+6x+9-x^2+6x-9=36\Leftrightarrow12x=36\Leftrightarrow x=3\left(ktm\right)\)
pt vô nghiệm
d, \(\Rightarrow6x-3-5x+10=x+7\Leftrightarrow x+7=x+7\)
pt vô số nghiệm
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a.\(\left|2-3x\right|=-1\left(vô.lí\right)\)
Vậy pt vô nghiệm
b.\(\Leftrightarrow4x=5,8\)
\(\Leftrightarrow x=1,45\)
c.\(ĐK:x\ne1\)
\(\Rightarrow\dfrac{3}{x-1}+\dfrac{2}{x^2+x+1}=\dfrac{3x^2}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(\Leftrightarrow\dfrac{3\left(x^2+x+1\right)+2\left(x-1\right)}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{3x^2}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(\Leftrightarrow3\left(x^2+x+1\right)+2\left(x-1\right)=3x^2\)
\(\Leftrightarrow3x^2+3x+3+2x-2-3x^2=0\)
\(\Leftrightarrow5x=-1\)
\(\Leftrightarrow x=-\dfrac{1}{5}\left(tm\right)\)
Vậy \(S=\left\{-\dfrac{1}{5}\right\}\)
Cua hang con lai so tap giay la
1362-318= 1044 (tap giay)
Co so tui la
1044 : 6 = 174