tìm x,biết:
|x+4|+|x-3|=10
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4 ( x- 1 0 ) - 3 ( 5 +x ) + 2 ( 4x- 3 ) = 5. ( x- 2 )
4x - 40 - 15 - 3x + 8x - 6 = 5x - 10
4x - 3x + 8x - 5x = -10 + 40 + 15 + 6
4x = 51
x = 51/4
tick đúng cho mình nha
\(\left(x+3\right)\cdot10=\left(x-4\right)\cdot5\)
\(\Rightarrow\) \(10x+30=5x-20\)
\(\Rightarrow\) \(10x-5x=-20-30\)
\(\Rightarrow\) \(5x=-50\)
\(\Rightarrow\) \(x=-50\div5\)
\(\Rightarrow\) \(x=-10\)
( x + 3 ) x 10 = ( x - 4 ) x 5
10x + 30 = 5x - 20
10x - 5x = - 30 - 20
5x = - 50
x = - 50 : 5
x = - 10
Tìm xx biết: \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19
Trả lời: x=x=
1) \(\left|x\right|< 10\)
\(\Leftrightarrow-10< x< 10\)
2) \(\left|x\right|>11\)
\(\Leftrightarrow\left[{}\begin{matrix}x< -11\\x>11\end{matrix}\right.\)
3) \(\left|x\right|\ge2x\left(\forall x\ge0\right)\)
\(\)\(\Leftrightarrow\left[{}\begin{matrix}x\le-2x\\x\ge2x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}3x\le0\\x\le0\end{matrix}\right.\)
\(\Leftrightarrow x=0\) \(\left(thỏa.đk:x\ge0\right)\)
4) \(\left|x\right|\le-3x\left(\forall x\le0\right)\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-\left(-3x\right)\\x\le-3x\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x\le0\\4x\le0\end{matrix}\right.\)
\(\Leftrightarrow x\le0\) \(\left(thỏa.đk\right)\)
Bài 1:
a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)
\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{6}{7}\)
b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)
\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)
\(\Rightarrow x=\dfrac{1}{6}\)
` (3/4 +x) xx 50/100 = 8/10`
`( 3/4 + x) xx 1/2 = 4/5`
` 3/4 + x = 4/5 : 1/2`
` 3/4 + x = 4/5 xx2`
` 3/4 + x = 8/5`
` x = 8/5 - 3/4`
` x = 17/20`
a) \(14\times X+X\times26=2520\)
\(X\times\left(14+26\right)=2520\)
\(X\times40=2520\)
\(X=2520:40\)
\(X=63\)
b) \(X\times\dfrac{3}{4}+X\times\dfrac{5}{4}=\dfrac{7}{8}\)
\(X\times\left(\dfrac{3}{4}+\dfrac{5}{4}\right)=\dfrac{7}{8}\)
\(X\times\dfrac{8}{4}=\dfrac{7}{8}\)
\(X\times2=\dfrac{7}{8}\)
\(X=\dfrac{7}{8}:2\)
\(X=\dfrac{7}{16}\)