CMR : A = 1/25 + 1/26 + 1/27 +......+1/54 < 39/40
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<1/25+1/25+...+1/25+1/40+1/40+1/40+...+1/40
=1/25.15+1/40.15=15/25+15/40=3/5+3/8=39/40
đặt vế trái là A ta có A<1/25.16+1/45.14=214/225=1-11/225 39/40=1-1/40 ta có 1.225<11.40=>1/40<11/225=>1-1/40>1-11/225=>214/225<39/40 mà A<214/225=>A<39/40(đpcm nhớ k cho mk nha
a)A = 1 / (1*2) + 1 / (3*4) + ... + 1 / (99*100) > 1 / (1*2) + 1 / (3*4) = 1 / 2 + 1 / 12 = 7 / 12 ♦
A = 1 / (1*2) + 1 / (3*4) + ... + 1 / (99*100) = (1 - 1 / 2) + (1 / 3 - 1 / 4) + ... + (1 / 99 - 100) =
(1 - 1 / 2 + 1 / 3) - (1 / 4 - 1 / 5) - (1 / 6 - 1 / 7) - ... - (1 / 98 - 1 / 99) - 1 / 100 <
1 - 1 / 2 + 1 / 3 = 5 / 6 ♥
♦, ♥ => 7 / 12 < A < 5 / 6
b)ta có:
1/1.2+1/3.4+1/5.6+...+1/49.50
=>1-1/2+1/3-1/4+1/5-1/6+...+1/49-1/50
=>(1+1/3+1/5+1/7+...+1/49)-(1/2+1/4+1/6+...+1/50)
=>(1+1/2+1/3+...+1/49+1/50)-(1/2+1/4+1/6+...+1/50).2
=>(1+1/2+1/3+...+1/49+1/50) -( 1+1/2+1/3+...+1/25)
=>1/26+1/27+1/28+...+1/50=1/26+1/27+1/28+...+1/50
hay 1/1.2+1/3.4+1/5.6+...+1/49.50=1/26+1/27+1/28+...+1/50
\(a.17+26:2\\ =17+13\\ =30\\ b.300:\left[130-6\left(45-40\right)\right]\\ =300:\left[130-6.5\right]\\ =300:\left[130-30\right]\\ =300:100\\ =3\\ c.\left(-15\right).\left(-2\right)\\ =15.2\\ =30\\ d.\left(-27\right).36+54.\left(-27\right)\\ =\left(-27\right)\left(36+54\right)\\ =\left(-27\right).90\\ =-2430\)
a) 17+14=31
b) 300:[130-6.5)
300:[130-30]
300:100
3
c)30
d)(36+54).(-27)
=90.(-27)
=-2430
Ta có : 1/25 + 1/26 + 1/27 +.....+1/39 < 1/25 + 1/25 + .....+1/25 = 15/25 = 3/5
1/40+1/41 +.....+1/54 < 1/40 + 1/40 +....+1/40 = 15/40 = 3/8
=> A = 1/25 + 1/26 + 1/27 +.......+1/54 < 3/5 + 3/8 = 39/40
=> A < 39/40 (đpcm)