775 chia 7
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(5^{15}+25^7+5^{13}=5^{15}+\left(5^2\right)^7+5^{13}\)
\(=5^{15}+5^{14}+5^{13}=5^{11}\left(5^4+5^3+5^2\right)\)
\(=5^{11}.\left(625+125+25\right)=5^{11}.775⋮775\)
A=1/7 +1/91 +1/247 + 1/475 + 1/775 + 1/1147
A=1/(1.7)+1/(7.13)+1/(13.19)+...+1/(31...
A=(1/6)*( 1 - 1/7 + 1/7 - 1/13 +... +1/31-1/37)
A=(1/6)*(1-1/37)
A=(1/6)*(36/37)
A=6/37
.
\(\dfrac{1}{7}+\dfrac{1}{91}+\dfrac{1}{247}+\dfrac{1}{475}+\dfrac{1}{775}+\dfrac{1}{1147}\)
\(=\dfrac{1}{1.7}+\dfrac{1}{7.13}+\dfrac{1}{13.19}+\dfrac{1}{19.25}+\dfrac{1}{25.31}+\dfrac{1}{31.37}\)
\(=\dfrac{1}{6}\left(1-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{25}+\dfrac{1}{25}-\dfrac{1}{31}+\dfrac{1}{31}-\dfrac{1}{37}\right)\)
\(=\dfrac{1}{6}\left(1-\dfrac{1}{37}\right)\)
\(=\dfrac{1}{6}.\dfrac{36}{37}\)
\(=\dfrac{6}{37}\)
\(#Wendy.Dang\)
1/7 +1/91 +1/247 + 1/475 + 1/775 + 1/1147
Đặt A=1/7 +1/91 +1/247 + 1/475 + 1/775 + 1/1147
A=1/(1.7)+1/(7.13)+1/(13.19)+...+1/(31...
A=(1/6)x( 1 - 1/7 + 1/7 - 1/13 +... +1/31-1/37)
A=(1/6)x(1-1/37)
A=(1/6)x(36/37)
A=6/37
muon 1ab5c chia het cho 775 thi 1ab5c phai chia het cho 31 va 25
muon 1ab5c chia het cho 25 thi 5c phai chia het cho 25 nen c=0
Vi 1ab50 chia het cho 31 nen a=0:b=8:c=0
a=3:b=9:c=0
a=7:b=0:c=0
= 6/37 nha
đúng 10000000000000000000000000% đó nếu có sai thì trách cái máy tính của mk nha vì k pải mk tính mờ là nó tính....
tk mk nha đg âm 439 kìa....
T_T
D = 1/7 + 1/91 + 1/247 + 1/475 + 1/775 + 1/1147
=\(\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+\frac{1}{19.25}+\frac{1}{25.31}+\frac{1}{31.37}\)
=\(\frac{1}{6}.\frac{6}{1.7}+\frac{1}{6}.\frac{6}{7.13}+\frac{1}{6}.\frac{6}{13.19}+\frac{1}{6}.\frac{6}{19.25}+\frac{1}{6}.\frac{6}{25.31}+\frac{1}{6}.\frac{6}{31.37}\)
=\(\frac{1}{6}\left(\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+\frac{6}{19.25}+\frac{6}{25.31}+\frac{6}{31.37}\right)\)
=\(\frac{1}{6}\left(\frac{1}{1}-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+\frac{1}{19}-\frac{1}{25}+\frac{1}{25}-\frac{1}{31}+\frac{1}{31}-\frac{1}{37}\right)\)
=\(\frac{1}{6}\left(\frac{1}{1}-\frac{1}{37}\right)\)
=\(\frac{1}{6}\left(\frac{37}{37}-\frac{1}{37}\right)=\frac{1}{6}.\frac{36}{37}=\frac{6}{37}\)
\(D=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+\frac{1}{475}+\frac{1}{775}+\frac{1}{1147}\)
\(=\frac{1}{6}\left(\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+\frac{6}{19.25}+\frac{6}{25.31}+\frac{6}{31.37}\right)\)
\(=\frac{1}{6}\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+\frac{1}{19}-\frac{1}{25}+\frac{1}{25}-\frac{1}{31}+\frac{1}{31}-\frac{1}{37}\right)\)
\(=\frac{1}{6}\left(1-\frac{1}{37}\right)=\frac{1}{6}.\frac{36}{37}=\frac{6}{37}\)
\(\approx\)110
775 : 7 = 110
( có dư )