13/20 + x = 2/5 + 3/20 . Giúp mình nhé
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\(\frac{4}{3.7}+\frac{5}{7.12}+\frac{1}{12.13}+\frac{7}{13.20}+\frac{3}{20.23}\)
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+...+\frac{1}{20}-\frac{1}{23}\)
\(=\frac{1}{3}-\frac{1}{23}+0+0+0\)
\(=\frac{20}{69}\)
Dấu "." là dấu nhân nha
Đặt \(A=\frac{4}{3\cdot7}+\frac{5}{7\cdot12}+\frac{1}{12\cdot13}+\frac{7}{13\cdot20}+\frac{3}{20\cdot23}\)
\(A=\frac{7-3}{3\cdot7}+\frac{12-7}{7\cdot12}+\frac{13-12}{12\cdot13}+\frac{20-13}{13\cdot20}+\frac{23-20}{20\cdot23}\)
\(A=\frac{1}{3}-\frac{1}{7}+....+\frac{1}{20}-\frac{1}{23}\)
\( A=\frac{1}{3}-\frac{1}{23}=\frac{20}{69}\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
a, 2015 - 2 × X = 101
2 x X = 2015 - 101
2 x X = 1914
X = 1914 : 2
X = 957
1a. 2015 - 2 x X = 101
2 x X = 2015 - 101
X = 1914 : 2
X = 957
b. 7 - (11 + X - 13) : \(2\frac{2}{3}\)= 2
(11 + X - 13) : \(2\frac{2}{3}\) = 7 - 2
11 + X - 13 = 5 x \(2\frac{2}{3}\)
11 + X = \(\frac{40}{3}\)+ 13
X = \(\frac{79}{3}\)- 11
X = \(\frac{46}{3}\)
c. 2012 - 5 x X = 17
5 x X = 2012 - 17
X = 1995 : 5
X = 399
d. \(5\frac{3}{4}\)+ (X - 2) x \(\frac{1}{3}\)= \(17\frac{3}{4}\)
(X - 2) x \(\frac{1}{3}\) = \(17\frac{3}{4}\)- \(5\frac{3}{4}\)
X - 2 = 12 : \(\frac{1}{3}\)
X = 36 + 2
X = 38
e. 12 x (X - 5) + 73 = 20
12 x (X - 5) = 20 - 73
X - 5 = -53 : 12
X = \(\frac{-53}{12}\)+ 5
X = \(\frac{7}{12}\)
Ta có: \(\dfrac{3-x}{20}=\dfrac{-5}{x-2}\)
\(\Leftrightarrow\dfrac{x-3}{-20}=\dfrac{-5}{x-2}\)
\(\Leftrightarrow\left(x-3\right)\left(x-2\right)=100\)
\(\Leftrightarrow x^2-5x+6-100=0\)
\(\Leftrightarrow x^2-5x-94=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5-\sqrt{401}}{2}\\x=\dfrac{5+\sqrt{401}}{2}\end{matrix}\right.\)
a,x- 2/3= -1/2
x= -1/2 + 2/3
x= 1/6
b,20%.x - x +1/5 =3/4
1/5.x - x +1/5 = 3/4
1/5.x-x =3/4 - 1/5
x.(1/5 - 1)=11/20
x.-4/5 =11/20
x=11/20 : -4/5=-11/16
a) \(x-\frac{2}{3}=-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
b) \(20\%x-x+\frac{1}{5}=\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{5}x-x=\frac{3}{4}-\frac{1}{5}\)
\(\Leftrightarrow-\frac{4}{5}x=\frac{11}{5}\)
\(\Leftrightarrow x=\frac{11}{5}:\left(-\frac{4}{5}\right)\)
\(\Leftrightarrow x=-\frac{11}{4}\)
\(\frac{13}{20}\)+ x = \(\frac{2}{5}\)+\(\frac{3}{20}\)
\(\frac{13}{20}\)+ x = \(\frac{11}{20}\)
x=\(\frac{11}{20}\)-\(\frac{13}{20}\)
x=\(\frac{-2}{10}\)
x=\(\frac{-1}{10}\)