23.5-[x+32]=10
tìm x
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a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
`#3107.101107`
\(3\left(x-32\right)-7=23\cdot5-50\)
\(\Rightarrow3\left(x-32\right)-7=115-50\)
\(\Rightarrow3\left(x-32\right)-7=65\)
\(\Rightarrow3\left(x-32\right)=65+7\)
\(\Rightarrow3\left(x-32\right)=72\)
\(\Rightarrow x-32=72\div3\)
\(\Rightarrow x-32=24\)
\(\Rightarrow x=24+32\)
\(\Rightarrow x=56\)
Vậy, `x = 56.`
\(3\left(x-32\right)-7=23.5-50\)
\(3\left(x-32\right)-7=115-50\)
\(3\left(x-32\right)-7=65\)
\(3\left(x-32\right)=65+7\)
\(3\left(x-32\right)=72\)
\(x-32=72:3\)
\(x-32=24\)
\(x=24+32\)
\(x=56\)
5( x+7) -10 = 23 . 5
=> 5x + 35 - 10 = 8 .5
=> 5x + 25 = 40
=> 5x = 40 - 25 =15
=> x = 15 : 5 = 3
Vậy x = 3
\(5.\left(x+7\right)-10=2^3.5\)
\(5.\left(x+7\right)-10=8.5=40\)
\(5.\left(x+7\right)=40+10=50\)
\(x+7=50:5=10\)
\(x=10-7=3\)
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a)
208 − 8. ( x + 4 ) = 2 3 .5 8. ( x + 4 ) = 208 − 40 = 168 x = 17
b)
208 − 8. ( x + 4 ) = 2 3 .5 8. ( x + 4 ) = 208 − 40 = 168 x = 17
c)
2018. ( 2019 − x ) = 0 x = 2019
9. (x + 28) = 0
x + 28 = 0: 9
x + 28 = 0
x = 0 – 28
x = -28
Vậy x = -28.
720:[41-(2x-5)]=23.5
720:[41-(2x-5)]=8.5
720:[41-(2x-5)]=40
41-(2x-5)=720:40
41-(2x-5)=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
Vậy x=14
Giải
32:(x-10)=32.
=>x-10=32:32.
=>x-10=1.
=>x=1+10.
=.x=11.
Vậy x=11
32.(x-10)=32
=>x-10=32:32
=>x-10=1
=>x=11
(x-78).26=0
=>x-78=0:26
=>x-78=0
=>x=78
(x-14):2=3
=>x-14=3.2
=>x-14=6
=>x=14+6
=>x=20
a) 32.(x-10)=32
x-10=1
x=11
b) (x-78).26=0
x-78=0
x=78
c) (x-14):2=3
x-14=6
x=20
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5