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Bài 2:
a: Xét ΔBAC có BE/BA=BF/BC
nên EF//AC và EF=AC/2
Xét ΔDAC có DG/DC=DH/DA
nên HG//AC và HG=AC/2
=>EF//HG và EF=HG
=>EFGH là hình bình hành
b: Xét ΔDAB có DH/DA=DN/DB
nên HN//AB và HN=AB/2
Xét ΔCAB có CM/CA=CF/CB
nên MF//AB và MF=AB/2
=>HN//MF và HN=MF
=>HNFM là hình bình hành
=>HF cắt NM tại trung điểm của mỗi đường
=>O là trung điểm của MN
![](https://rs.olm.vn/images/avt/0.png?1311)
Tóm tắt:
h = 2m
l = 8m
m =400kg
F = 120N
Giải:
Trọng lượng của thùng là :\(P=10\cdot m=10=400=4000\left(N\right)\)
Công tối thiểu để kéo vật lên là : \(A_{ci}=P\cdot h=4000\cdot2=8000\left(J\right)\)
Công kéo thùng khi bằng tấm ván: \(A_{tp}=F\cdot l=1200\cdot8=9600\left(N\right)\)
Ta có : \(A_{tp}=A_{ci}+A_{ms}\)
\(\Rightarrow\) Công ma sát khi đẩy vật lên bằng ván : \(A_{ms}=A_{tp}-A_{ci}=9600-8000=1600\left(J\right)\)
Lực ma sát khi đẩy vật lên bằng ván : \(F_{ms}=\dfrac{A_{ms}}{l}=\dfrac{1600}{8}=200\left(N\right)\)
b, Hiệu suất của mpn là : \(H=\dfrac{A_{ci}}{A_{tp}}=\dfrac{8000}{9600}\cdot100\%=83,\left(3\right)\%\)
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a, \(3x+7x^2+5+2x-7x^2\ge0\Leftrightarrow5x+5\ge0\Leftrightarrow x\ge-1\)
b, \(12x\ge-16\Leftrightarrow x\ge-\dfrac{4}{3}\)
c, \(\dfrac{5x-1-6}{6}-\dfrac{4\left(x+1\right)}{3}\le0\)
\(\Leftrightarrow\dfrac{5x-7-8\left(x+1\right)}{6}\le0\Rightarrow-3x-15\le0\Leftrightarrow x\le-5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(n_{H_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
PTHH: Fe + 2HCl → FeCl2 + H2
Mol: 0,15 0,3 0,15
\(m_{Fe}=0,15.56=8,4\left(g\right);m_{Cu}=10-8,4=1,6\left(g\right)\)
b,\(m_{HCl}=0,3.36,5=10,95\left(g\right)\)
\(\Rightarrow m_{ddHCl}=\dfrac{10,95.100\%}{36,5\%}=30\left(g\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(x+10\ge x^2\Leftrightarrow x^2-x-10\le0\Leftrightarrow\dfrac{1-\sqrt[]{41}}{2}\le x\le\dfrac{1+\sqrt[]{41}}{2}\rightarrow Câu.D.Sai\)
2) \(-\pi< -2\Leftrightarrow\pi>2\Leftrightarrow\pi^2>4\rightarrow Câu.A.Sai\)
5) Câu D
7) Câu C
8) Câu D
9) Câu D
10) Câu D
11) Câu C
12) Câu A
13) Câu C
![](https://rs.olm.vn/images/avt/0.png?1311)
uses crt;
var a:array[1..200]of integer;
i,t:integer;
begin
clrscr;
for i:=1 to 200 do
begin
write('A[',i,']='); readln(a[i]);
end;
writeln('Cac phan tu le nho hon 200 la: ');
for i:=1 to n do
if (a[i] mod 2<>0) and (a[i]<200) then write(a[i]:4);
writeln;
t:=0;
for i:=1 to n do
if (50<a[i]) and (a[i]<80) then t:=t+sqr(a[i]);
writeln('Tong binh phuong cac phan tu thuoc khoang (50;80) la: ',t);
readln;
end.
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1 more important
2 more engaging
3 more interested
4 the most effective
5 the most creative
6 more useful
7 more creative
8 more likely
9 the most natural
10 better
\(\text{≌₰⇴⩸⨙⩸※◡⨦}\)
1-Active Learning is more important than traditional teaching methods. (comparative)
2-Active Learning activities are more engaging than lectures. (comparative)
3-Active Learning helps kids become more interested in learning. (comparative)
4-Active Learning is the most effective teaching method for young students. (superlative)
5-Kids who use Active Learning are the most creative learners. (superlative)
6-Active Learning is more useful for students who are just starting their school journey in elementary school. (comparative)
7-Active Learning helps kids become more creative and develop important skills. (comparative)
8-Kids who are actively engaged in learning are more likely to remember what they learned. (comparative)
9-Active Learning is one of the most natural ways for kids to learn. (superlative)
10-Active Learning activities are better for kids because they are fun and exciting. (comparative)