Tính: 11.3^29-9^15 / (2.3^14)^5
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ta co:A = 11.329-915/ (2.314)2
=11.329-(32)15/22.328
=11.329-330/22.328
=329.(11-3)/22.328
= 3.7/4
=21/4
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\(\dfrac{11\cdot3^7\cdot9^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(=\dfrac{11\cdot3^7\cdot3^{14}-3^{30}}{2^2\cdot3^{28}}\)
\(=\dfrac{3^{21}\left(11-3^9\right)}{2^2\cdot3^{28}}\)
\(=\dfrac{11-3^9}{2^2\cdot3^7}\)
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B = 11 . 322 . 37 - 915 / (2 . 314)2
B = 11 . 329 - (32)15 / 22 . 328
B = 11 . 329 - 330 / 22 . 328
B = 329 . (11 - 3) / 22 . 328
B = 329 . 8 / 22 . 328
B = 329 . 23 / 22 . 328
B = 3 . 2
B = 6
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\(=\dfrac{11\cdot3^{21}-3^{30}}{2^2\cdot3^{28}}=\dfrac{3^{21}\left(11-3^7\right)}{2^2\cdot3^{28}}=\dfrac{-2176}{2^2\cdot3^7}=\dfrac{-2176}{8748}=\dfrac{-544}{2187}\)