Tìm số nguyên xx, biết: x - (22 - x) = x - 27x−(22−x)=x−27
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a)
\(x-5=-1\)
\(x=-1+5\)
\(x=4\)
b)
\(x+30=4\)
\(x=4-30\)
\(x=-26\)
c)
\(x-(-24)=3\)
\(x+24=3\)
\(x=3-24\)
\(x=-21\)
d)
\(22-(-x)=12\)
\(22+x=12\)
\(x=12-22\)
\(x=-10\)
e)
\(( x + 5 ) + ( x - 9 ) = x + 2\)
\(x+5+x-9=x+2\)
\(x+x-x=2+9-5\)
\(x=6\)
f)
\(( 27 - x ) + ( 15 + x ) = x - 24\)
\(27-x+15+x=x-24\)
\(-x+x-x=-24-15-27\)
\(-x=-66\)
\(x=66\)
x - 5 = -1 x - (-24) = 3
x = -1 + 5 x + 24 = 3
x = 4 x = 3 - 24
x + 30 = 4 x = - 21
x = 4 - 30 22 - ( -x) = 12
x = - 26 22 + x = 12
x + 5 + ( x - 9) = x + 2 x = 12 - 22
x + 5 + x - 9 = x + 2 x = -10
2x - x = 2 - 5 + 9 ( 27 - x) + ( 15 + x) = x - 24
x = - 3 + 9 27 - x + 15 + x = x - 24
x = 6 27 + 15 = x - 24
x - 24 = 42
x = 42 + 24
x = 66
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.
a) \(\left(x-3\right)^2-4=0\)
\(\left(x-3\right)^2=0+4\)
\(\left(x-3\right)^2=4\)
\(\left(x-3\right)^2=\pm4\)
\(\left(x-3\right)^2=\pm2^2\)
\(\orbr{\begin{cases}x-3=2\\x-3=-2\end{cases}}\)
\(\orbr{\begin{cases}x=5\\x=1\end{cases}}\)
b) \(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)
\(4x^2+12x+9-4x^2+1=22\)
\(12x+10=22\)
\(12x=22-10\)
\(12x=12\)
\(x=1\)
c) \(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=16\)
\(16x^2-9-16x^2+40x-25=16\)
\(-34+40x=16\)
\(40x=16+34\)
\(40x=50\)
\(x=\frac{50}{40}=\frac{5}{4}\)
d) \(x^3-9x^2+27x-27=-8\)
\(x^3-9x^2+27x-27+8=0\)
\(x^3-9x^2+27x-19=0\)
\(\left(x^2-8x+19\right)\left(x-1\right)=0\)
Vì \(\left(x^2-8x+19\right)>0\) nên:
\(x-1=0\)
\(x=1\)
e) \(\left(x+1\right)^3-x^2\left(x+3\right)=2\)
\(x^3+2x^2+x+x^2+2x+1-x^2-3x^2=2\)
\(3x+1=2\)
\(3x=2-1\)
\(3x=1\)
\(x=\frac{1}{3}\)
a)\(x-5=-1\)
⇔\(x=4\)
b)\(x+30=-4\)
⇔\(x=-34\)
c)\(x-\left(-24\right)=3\)
⇔\(x+24=3\)
⇔\(x=-21\)
e)\(\left(x+5\right)+\left(x-9\right)=x+2\)
⇔\(x+5+x-9-x-2=0\)
⇔\(x-6=0\)
⇔\(x=6\)
f)\(\left(27-x\right)+\left(15+x\right)=x-24\)
⇔\(27-x+15+x-x+24=0\)
⇔\(66-x=0\)
⇔\(x=66\)
\(a.x-5=-1\) \(b.x+30=-4\)
\(x=\left(-1\right)+5\) \(x=\left(-4\right)-30\)
\(x=4\) \(x=-34\)
\(c.x-\left(-24\right)=3\) \(e.\left(x+5\right)+\left(x-9\right)=x+2\)
\(x=3+\left(-24\right)\) \(x+5+x-9=x+2\)
\(x=-21\) \(2x-4=x+2\)
\(2x-x=2+4\)
\(x=6\)
\(f.\left(27-x\right)+\left(15+x\right)=x-24\)
\(27-x+15+x=x-24\)
\(27+15=x-24\)
\(42=x-24\)
\(x=24+42\)
\(x=66\)
(27-X)+(15+x)=x-24
27-x+15+x=x-24
-x+x-x=-24-27-15
-x=-66
x=-(-66)
x=66
a) x – 5 = - 1 ;
=> x = -1 + 5 = 4
Vậy x = 4
b) x + 30 = - 4;
=> x = - 4 - 30 = - 34
Vậy x = - 34
c) x – ( - 24) = 3 ;
=> x + 24 = 3
=> x = 3 - 24
=> x = - 21
Vậy x = - 21
d) 22 – ( - x ) = 12;
=> 24 + x = 12
=> x = 12
Vậy x = 12
e) ( x + 5 ) + ( x – 9 ) = x + 2 ;
=> x + 5 +x - 9 = x + 2
=> 2x - x = 1 + 9 - 5
=> x = 5
Vậy x = 5
f) ( 27 – x ) + ( 15 + x ) = x – 24 .
=> 27 - x + 15 + x = x - 24
=> x + 42 = x - 24
=> x - x = 42 - 24
=> 0 = 8 ( vô lí)
Vậy x thuộc rỗng
Rảnh nhỉ
@@ Học tốt
## Chiyuki Fujito
a)\(x-\left(-24\right)=3\)
\(x+24=3\)
\(x=3-24\)
\(x=-21\)
b)\(22-\left(-x\right)=12\)
\(\Rightarrow22+x=12\)
\(\Rightarrow x=12-22\)
\(\Rightarrow x=-10\)
c) \(\left(27-x\right)+\left(15+x\right)=x-24\)
\(\Rightarrow27-x+15+x=x-24\)
\(\Rightarrow42=x-24\)
\(\Rightarrow66=x\)
d)\(x+x-\left(-4\right)=x+2\)
\(\Rightarrow x+x+4=x+2\)
\(\Rightarrow x+x-x=2-4\)
\(\Rightarrow x=-2\)
câu 2 :
\(-37+54+\left(-70\right)+9-163+246\)
\(=\left(-37-163\right)+\left(246+54\right)+\left(-70\right)+9\)
\(=-200+200+-61\)
\(=-61\)
số trả lời x là -5
x là 5 nha