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a. y x 47 = 24064
y = 24064 : 47
y = 512
b. Y x 2 7 = 3 4 x 4 15 Y x 2 7 = 1 5 Y = 1 5 : 2 7 Y = 1 5 x 7 2 Y = 7 10
\(\dfrac{4}{51}\times y+y+y\times\dfrac{47}{51}=\dfrac{5}{4}+\dfrac{1}{6}\\y\times\left(\dfrac{4}{51}+1+\dfrac{47}{51}\right)= \dfrac{17}{12}\\ y\times2=\dfrac{17}{12}\\ y=\dfrac{17}{24}\)
Giải:
a) \(-47+5y=3y-69\)
\(\Leftrightarrow5y-3y=-69+47\)
\(\Leftrightarrow2y=-22\)
\(\Leftrightarrow y=-\dfrac{22}{2}=-11\)
Vậy ...
b) \(\left(96-8y\right)+5y=-174\)
\(\Leftrightarrow96-8y+5y=-174\)
\(\Leftrightarrow96-3y=-174\)
\(\Leftrightarrow-3y=-174-96=-270\)
\(\Leftrightarrow y=\dfrac{-270}{-3}=90\)
Vậy ...
c) \(\left|7-2\right|=y+2\)
\(\Leftrightarrow5=y-2\)
\(\Leftrightarrow y=5+2=7\)
Vậy ...
\(a.216\times y+y=3689\)
\(y\times\left(216+1\right)=3689\)
\(y\times217=3689\)
\(y=3689:217\)
\(y=17\)
\(b.y\times47-37\times y=20210\)
\(y\times\left(47-37\right)=20210\)
\(y\times10=20210\)
\(y=20210:10\)
\(y=2021\)
a)
216 * y + y = 3689
y * (216+1)=3689
y*217=3689
y=3689:217
y=17
b)
y * 47 - 37 * y = 20210
*y (47-37)=20210
y * 10 = 20210
y = 20210 :10
y= 2021
\(\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}=\frac{3x+3}{9}=\frac{2y+4}{-8}=\frac{4z-12}{20}=\frac{3x+3+2y+4+4z-12}{-8+9+20}=\frac{42}{21}=2\)
=>x+1=6=>x=5
y+2=2.(-4)=-8=>y=-10
z-3=10=>x=13
vậy x=5;y=-10;z=13
áp dụng tính chất của dãy tỉ số bằng nhau ta có:
\(\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}=\frac{3.\left(x+1\right)+2.\left(y+2\right)+4.\left(z-3\right)}{3.3+2.\left(-4\right)+4.5}\)
\(=\frac{3x+3+2y+4+4z-12}{9-8+20}=\frac{\left(3x+2y+4z\right)+\left(3+4-12\right)}{21}\)
\(=\frac{47-5}{21}=2\)
suy ra: \(\frac{x+1}{3}=2\Rightarrow x+1=6\Rightarrow x=5\)
\(\frac{x+2}{-4}=2\Rightarrow x+2=-8\Rightarrow x=-6\)
\(\frac{z-3}{5}=2\Rightarrow z-3=10\Rightarrow z=13\)
y;57% +y; 25% -y ; 29% +y; 47%= 45%
\(=>y:\left(57\%+25\%-29\%+47\%\right)=45\%\)
\(y:100\%=45\%\)
\(y=45\%\times100\%\)
\(y=450\%\)
giúp ạ:(
https://hoc24.vn/cau-hoi/65x1910-35x710351069.6294302466757