bái 2 làm tinh nhân
a; (5x mũ 2 -4x).(x-3)
b;(2-3xy).(3x mũ 4 +4y mũ 2 +5xy)
c;(-3x mũ 2 +x+1).(x mũ 2+x-5)
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a: \(-4x^3\left(x^2-3x+2\right)=-4x^5+12x^4-8x^3\)
b: \(-\dfrac{2}{5}x^2\left(5x^3+10x^2-15x\right)=-2x^5-4x^4+6x^3\)
a) \(\left(-3x^2\right).\left(4x^4\right)=-12x^6\)
b) \(\dfrac{1}{2}x^3.6x^5=3x^8\)
c) \(\left(-5x^4\right).\left(-7x^2\right)=35x^6\)
a: \(=-4x^2+20x+2x-10=-4x^2+22x-10\)
b: =x^2-9
c: =x^3+27
d: \(=-2x^2-6x+x+3=-2x^2-5x+3\)
e: =8a^3+1
f: =(3-x)(x+1)(x+2)
=(3-x)(x^2+3x+2)
=3x^2+9x+6-x^3-3x^2-2x
=-x^3+7x+6
1+4=5
2+5=5+7=12
3+6=9+12=21
8+11=19+21=40
đs 40
dễ ẹt chẳng khó 1 chút nào cả
Bài 1:
\(a,=15x^4-12x^3+9x^2\\ b,=-15x^3y^2+25x^2y^2-5xy^3\\ c,=5x^3-15x^2-4x^2+12x=5x^3-19x^2+12x\\ d,=3x^3-9x^2y+xy^2-3y^3+5x^2y-15xy^2=3x^3-3y^3-4x^2y-14xy^2\)
Bài 2:
\(a,=x^2+4x-21-x^2-4x+5=-16\\ b,=x^2+16x+64-2x^2-12x+32+x^2-4x+4=100\\ c,=x^4-16x^2-x^4+1=1-16x^2\\ d,=x^3+1-x^3+1=2\)
a, \(40x^2y-8xy-16x^2y^2=8xy\left(5x-1-2xy\right)\)
b, \(\left(x-y\right)\left(x+y\right)-3\left(x-y\right)=\left(x-y\right)\left(x+y-3\right)\)
c, \(\left(x-y\right)^2-5\left(x-y\right)=\left(x-y\right)\left(x-y-5\right)\)
a) 40x2y - 8xy - 16x2y2
= 8xy( 5x - 1 - 2xy)
b) (x-y)(x+y)-3(x-y)
= (x - y)( x + y - 3)
c)(x-y)2 -5(x-y)
=(x - y)(x - y - 5)
\(1,\\ a,=x^3-5x\\ b,=3x^3y-6x^3y^2+9xy\\ c,=6x^2-6x-36\\ d,=x^3+2x^2y-3xy^2\\ 2,\\ a,=4x^2-25\\ b,=x^2-6x+9\\ c,=9x^2+24x+16\\ d,=x^3-6x^2y+12xy^2-8y^3\\ e,=125x^3+225x^2y+135xy^2+27y^3\\ f,=125-x^3\)
\(g,=8y^3+x^3\\ 3,\\ a,=x\left(x+2\right)\\ b,=\left(x-3\right)^2\\ c,=\left(x-y\right)\left(y+5\right)\\ d,=2x\left(y+1\right)-y\left(y+1\right)=\left(2x-y\right)\left(y+1\right)\\ e,=6x^2y^2\left(xy^2+2y-3x\right)\)
a.( 5x2-4x).(x-3)=5x3-15x2-4x2+12x=5x3-11x2+12x
b.(2-3xy).(3x4+4y2+5xy)=6x4+8y2+10xy-9x5y-12xy3-15x2y2
c.(-3x2+x+1).(x2+x-5)=-3x4-3x3+15+x3+x2-5x+x2+x-5=-3x4-2x3+2x-4x+10