31 x 8 + 31 x 5 = 31 +(8 + a)
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a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
a) 31 - ( 16 + 31 ) = x - ( 45 - 75 )
31 - 16 - 31 = x - 45 + 75
-16 = x + 30
x = -46
b) 9 - 45 = ( 8 - x ) - ( 35 + 8 )
-36 = 8 - x - 35 - 8
-36 = -x - 35
-x = -1
x = 1
Bài 8: Tính bằng cách thuận tiện nhất:
a, 6 x 31 x 5 =(6x5)x31
=30x31
=930
b, 8 x 63 x 5 =(8x5)x63
=40x63
=2520
a.
6 x 31 x 5
= (6 x 5) x 31
= 30 x 31
= 930
b.
8 x 63 x 5
= (8 x 5) x 63
= 40 x 63
= 2520
a) \(6-\dfrac{2}{5}+\dfrac{3}{5}\) x \(3\)
\(=6-\dfrac{2}{5}+\dfrac{9}{5}\)
\(=\dfrac{30}{5}-\dfrac{2}{5}+\dfrac{9}{5}\)
\(=\dfrac{30-2+9}{5}=\dfrac{37}{5}\)
b) \(\left(\dfrac{31}{35}-\dfrac{4}{7}\right)\) x \(\dfrac{8}{7}:2\)
\(=\left(\dfrac{31}{35}-\dfrac{20}{35}\right)\) x \(\dfrac{8}{7}:2\)
\(=\dfrac{11}{35}\) x \(\dfrac{8}{7}:2\)
\(=\dfrac{11}{35}\) x \(\dfrac{8}{7}\) x \(\dfrac{1}{2}\)
\(=\dfrac{\text{11 x 8 x 1}}{\text{ 35 x 7 x 2}}=\dfrac{88}{490}=\dfrac{88}{245}\)
a) 6−25+356−25+35 x 33
=6−25+95=6−25+95
=305−25+95=305−25+95
=30−2+95=375=30−2+95=375
b) (3135−47)(3135−47) x 87:287:2
=(3135−2035)=(3135−2035) x 87:287:2
=1135=1135 x 8
\(\frac{31}{9}\left|x\right|-\frac{5}{2}=\frac{8}{3}\)
=> \(\frac{31}{9}\left|x\right|=\frac{8}{3}+\frac{5}{2}\)
=> \(\frac{31}{9}\left|x\right|=\frac{16}{6}+\frac{15}{6}\)
=> \(\frac{31}{9}\left|x\right|=\frac{31}{6}\)
=> \(\left|x\right|=\frac{31}{6}:\frac{31}{9}=\frac{31}{6}\cdot\frac{9}{31}=\frac{9}{6}=\frac{3}{2}\)
=> x = 3/2 hoặc x = -3/2
1.
a) -[ -345 + 1234 - 2014] - (345 - 1234)
= 345 - 1234 + 2014 - 345 + 1234
= ( 345 - 345) + ( -1234 +1234) +2014
= 0 + 0 + 2014 = 2014
b) ( -31) . 47 + ( -31) . 52 + ( -31)
= (-31) . ( 47 + 52 +1)
= (-31) . 100 = -3100
c) 654 +{ 374 - [ 654 - ( +126)]}
= 654 + [ 374 -( 654 - 126)]
= 654 + ( 374 - 654 + 126)
= 654 + 374 - 654 + 126
= ( 654 - 654 ) + ( 374 + 126 )
= 0 + 500 = 500
mik tìm đc câu trả lời rùi điểm này là tặng cho bạn đã trả lời cho mik❤
Đề:
Giài:
\(\frac{31}{9}\left|x\right|=\frac{8}{3}+\frac{5}{2}\)
\(\frac{31}{9}\left|x\right|=\frac{31}{6}\)
\(\left|x\right|=\frac{31}{6}:\frac{31}{9}\)
\(\left|x\right|=\frac{3}{2}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-3}{2}\end{cases}}\)
Vậy x = \(\frac{3}{2}\)hoặc x = \(\frac{-3}{2}\)
\(\frac{31}{9}\left|x\right|-\frac{5}{2}=\frac{8}{3}\)
\(\frac{31}{9}\left|x\right|=\frac{8}{3}+\frac{5}{2}\)
\(\frac{31}{9}\left|x\right|=\frac{8\cdot2}{6}+\frac{5\cdot3}{6}\)
\(\frac{31}{9}\left|x\right|=\frac{16}{6}+\frac{15}{6}\)
\(\frac{31}{9}\left|x\right|=\frac{31}{6}\)
\(\left|x\right|=\frac{31}{6}:\frac{31}{9}\)
\(\left|x\right|=\frac{31}{6}\cdot\frac{9}{31}\)
\(\left|x\right|=\frac{1}{2}\cdot\frac{3}{1}\)
\(\Leftrightarrow\hept{\begin{cases}x=\frac{3}{2}\\x=-\frac{3}{2}\end{cases}}\)
Vậy \(x\in\left\{\frac{3}{2};-\frac{3}{2}\right\}\)
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