7x+1-3.74=4.75
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`(-3 .7^4 + 7^3)/(7^5 .6 -7^3 .2)`
`=(7^3 .(-3.7 +1))/(7^3 (7^2 .6 -2))`
`=(-20)/292=-5/73`
Giải:
\(\dfrac{-3.7^4+7^3}{7^5.6-7^3.2}\)
\(=\dfrac{-3.7.7^3+7^3}{7^3.7^2.6-7^3.2}\)
\(=\dfrac{7^3.\left(-3.7+1\right)}{7^3.\left(7^2.6-2\right)}\)
\(=\dfrac{-21+1}{49.6-2}\)
\(=\dfrac{-20}{294-2}\)
\(=\dfrac{-20}{292}=\dfrac{-5}{73}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(x.\left(53+42+5\right)=4.75\)
\(x.100=4.75\)
\(x=4.75.100\)
\(x=475\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3,75 + 1,25*X=4*75
=>3,75+1,25*X=300
=>1,25 * X =300 - 3,75=296,25
=> X = 296,25 / 1,25 = 237
TICK NHA
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(243^5=\left(3^5\right)^5=3^{25}\)
\(3\cdot27^5=3\cdot\left(3^3\right)^5=3\cdot3^{15}=3^{16}\)
mà \(3^{25}>3^{16}\)
nên \(243^5>3\cdot27^5\)
b) \(625^5=\left(5^4\right)^5=5^{20}\)
\(125^7=\left(5^3\right)^7=5^{21}\)
mà \(5^{20}< 5^{21}\)
nên \(625^5< 125^7\)
c) \(202^{303}=\left(202^3\right)^{101}=8242408^{101}\)
\(303^{202}=\left(303^2\right)^{101}=91809^{101}\)
mà \(8242408^{101}>91809^{101}\)
nên \(202^{303}>303^{202}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
47x + 52x + x = 4.75 = 300
x . ( 47 + 52 + 1 ) = 300
x . 100 = 300
x = 300 : 100
x = 3
![](https://rs.olm.vn/images/avt/0.png?1311)
(115x+34)73=4.75
=>(115x+81).343=4.16807
=>(115x+81).343=67228
=>(115x+81)=67228:343
=>115x+81=196
=>115x=196-81
=>115x=115
=>x=115:115
=>x=1
Vậy x=1
=(115* x +81)*343=67228
=>(115* x+81)=67228:343=196
=>115*x=196-81=115
=>x=115/115=1
Vậy x=1