Tìm x
4x + 12 = 3( x - 7 )
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(Chuyển toán thành văn nhé )
Chuyển 81 sang vế phải , chia 4 căn 2 là ra 9/2

=>4x-2+8 chia hết cho 2x-1
=>2x-1 thuộc {1;-1}
=>x thuộc {1;0}

\(\dfrac{3}{7}:\dfrac{7}{x}:\dfrac{3}{4}=\dfrac{12}{105}\)
\(\dfrac{3}{7}.\dfrac{x}{7}=\dfrac{3}{35}\)
\(\dfrac{x}{7}=\dfrac{1}{5}\)
\(x=\dfrac{1}{5}.7=\dfrac{7}{5}\)
tìm x biết :
\(\dfrac{3}{7}\) : \(\dfrac{7}{x}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{105}\)
\(\dfrac{3}{7}\) : \(\dfrac{7}{x}\) = \(\dfrac{12}{105}\)\(\times\) \(\dfrac{3}{4}\)
\(\dfrac{3}{7}\) \(\times\) \(\dfrac{x}{7}\) = \(\dfrac{3}{35}\)
\(\dfrac{x}{7}\) = \(\dfrac{3}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{7}\) = \(\dfrac{1}{5}\)
\(x\) = \(\dfrac{1}{5}\) \(\times\) 7
\(x\) = \(\dfrac{7}{5}\)

Bài 1:
a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)
\(=\dfrac{9}{20}-\dfrac{2}{9}\)
\(=\dfrac{41}{180}\)
b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)
\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)
\(=\dfrac{5}{6}\times\dfrac{12}{7}\)
\(=\dfrac{10}{7}\)
c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)
\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{9}\times1\)
\(=\dfrac{7}{9}\)
Bài 2:
a) \(2\times\left(x-1\right)=4026\)
\(\left(x-1\right)=4026\div2\)
\(x-1=2013\)
\(x=2014\)
Vậy: \(x=2014\)
b) \(x\times3,7+6,3\times x=320\)
\(x\times\left(3,7+6,3\right)=320\)
\(x\times10=320\)
\(x=320\div10\)
\(x=32\)
Vậy: \(x=32\)
c) \(0,25\times3< 3< 1,02\)
\(\Leftrightarrow0,75< 3< 1,02\) ( S )
=> \(0,75< 1,02< 3\)

b: =>x(8-7)=-33
=>x=-33
c: =>-12x+60+21-7x=5
=>-19x=-76
hay x=4
d: =>-2x-2-x+5+2x=0
=>3-x=0
hay x=3


a: \(\Leftrightarrow\dfrac{x}{-4}=\dfrac{21}{y}=\dfrac{z}{-80}=\dfrac{3}{4}\)
=>x=-3; y=28; z=-60
b: 5/12=x/-72
=>x=-72*5/12=-6*5=-30
c: =>x+3=-5
=>x=-8
=>4x+12=3x-21
=>4x-3x=-12-21
=>x=-33
Vậy x=-33
4x + 12 = 3x - 21 => x = - 33